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Elodia [21]
2 years ago
11

A force of 10 newtons acts in a direction 75° above horizontal, moving an object 15 meters from (0, 0) to (15, 0). what is the w

ork done by the force?
Physics
1 answer:
hammer [34]2 years ago
6 0

Work done by the force is 150 Joules.

Steps involved in the question:

Step one:

Given data

Force F= 10N

the distance is described by the coordinate =  (0,0) to (15,0)

hence the distance = 15m in the x-direction.

Step two:

Required is the work done

we know that work done is expressed as

Wd= Force* Distance

Wd= 10*15

Wd= 150 Joules

To learn more about work done refer : brainly.com/question/25573309

#SPJ4



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Answer:

Work done by the gardner is 500 J

Explanation:

As we know that the gardner apply force perpendicular upward by magnitude 300 N and along the floor horizontal force is 100 N

so we have

F = 100 \hat i + 300 \hat j

now the displacement of the gardner along the floor is

d = 5\hat i

now work done is given as

W = F. d

so we have

W = (100 \hat i + 300 \hat j). (5\hat i)

W = 500 J

3 0
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A bicycle consists of which types of simple machines? Check all that apply. lever
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<span>A bike is compound machine.This means that it is made up of a bunch of different simple machines. Screws are used to hold the pieces together. The wheel of a bicycle is a wheel and axle. The pedals are also examples of this simple machine. The pedals are attached to a lever that turns a pulley.</span>
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A box of mass 12 kg is at rest on a flat floor. The coefficient of static friction between the box and floor is 0.42. What is th
vladimir2022 [97]

As we know that friction force on box is given by

F_s = \mu_s N

here we know that

N = mg

here we have

m = 12 kg

\mu_s = 0.42

so now we have

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now we will have

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F_s = 49.4 N

so it required minimum 49 N(approx) force to move the block

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3 years ago
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There are two uncharged objects, A and B. Some electrons move from A to B. How does the charge of the two objects change?
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5 0
3 years ago
Meteor Infrasound A meteor that explodes in the atmosphere creates infrasound waves that can travel multiple times around the gl
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Answer:

The frequency of these waves is 4.27\times10^{-2}\ Hz

Explanation:

Given that,

Wavelength = 6.6 km

Distance = 8810 km

Time t = 8.67 hr

We need to calculate the velocity of sound

Using formula of velocity

v = \dfrac{D}{T}

Where, D = distance

T = time

Put the value into the formula

v =\dfrac{8810}{8.67}

v=1016\ km/hr

We need to calculate the frequency

Using formula of frequency

v=n\lambda

n=\dfrac{v}{\lambda}

Put the value into the formula

n=\dfrac{1016}{6.6}

n=153.93\ hr

n=\dfrac{153.93}{60\times60}

n=0.0427\ Hz

n=4.27\times10^{-2}\ Hz

Hence, The frequency of these waves is 4.27\times10^{-2}\ Hz

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