Pregunta completa:
Un barco va a una velocidad de 45 ml/h, luego el capitán ordena acelerar hasta que la velocidad hasta que la velocidad sea de 60 mll/h. si la operación dura 30 minutos.
A cual fue la aceleracion?
B qué distancia recorre?
Responder:
30 millas / hora
26.25 mi
Explicación:
Dado que :
Velocidad inicial, u = 45 mi / hr
Velocidad final, v = 60 mi / hr
Tiempo, t = 30 minutos = 30/60 = 0,5 h
Aceleración, a = cambio de velocidad con el tiempo;
a = (v - u) / t
a = (60 - 45) / 0,5
a = 15 / 0,5
a = 30 millas / h²
Recorrido de distancia, S
S = ut + 0.5at²
S = 45 (0,5) + 0,5 (30) (0,5²)
S = 22,5 + 3,75
S = 26,25 millas
Explanation:
Given that,
Angle by the normal to the slip α= 60°
Angle by the slip direction with the tensile axis β= 35°
Shear stress = 6.2 MPa
Applied stress = 12 MPa
We need to calculate the shear stress applied at the slip plane
Using formula of shear stress

Put the value into the formula


Since, the shear stress applied at the slip plane is less than the critical resolved shear stress
So, The crystal will not yield.
Now, We need to calculate the applied stress necessary for the crystal to yield
Using formula of stress

Put the value into the formula


Hence, This is the required solution.
Answer: There are many precautionary measures which is to be taken care of while handling technetium-99.
Explanation:
There is a proper separated area for the handling of the 99Tc and all the containers are properly labelled for the use of technetium-99 only.
While working on it, the person is not allowed to eat or drink anything.
Use of gloves, glasses and other preventive measure is also very important when handling radioactive materials.
Try to maintain a proper distance throughout the experiment.
Answer:
The net force is 785 N
Explanation:
The net force = Force in one direction - force in the opposite direction
Here the Downward force due to gravity = 1000N
and the Upward force of air = 215 N
The net force = Downward force due to gravity -Upward force of air
Substituting the given values, we get -
The net force = 1000 -215 = 785 N
Hence, the net force is 785 N