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Nimfa-mama [501]
3 years ago
14

[W]?

Physics
1 answer:
natali 33 [55]3 years ago
5 0

87 km I think .........

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Explain<br> (0) what is meant by regeneration,<br> (ii) why an analogue signal cannot be regenerated
Kamila [148]

Explanation:

<h3>1.) Regeneration is the natural process of replacing or restoring damaged or missing cells, tissues, organs, and even entire body parts to full function in plants and animals.</h3>

2.) When noise is added to analogue signals, it usually sounds like background hiss. Such noise can not be removed so the original clean signal can not be re-created or re-generated.

6 0
3 years ago
A box weighing 12,000 N is parked on a 36° slope. What will be the component of the weight parallel to the plane that balances f
sweet-ann [11.9K]

Given :

A box weighing 12,000 N is parked on a 36° slope.

To Find :

What will be the component of the weight parallel to the plane that balances friction.

Solution :

The component of that will be parallel to the plane to balance friction is :

F \ cos ( 90 - 36)^o\\\\F\ ( sin\ 36^o)

Therefore, component of force to balance friction is F sin 36° .

Hence, this is the required solution.

5 0
2 years ago
How does changes in distance affect the gravitational pull between two objects? Describe and give one example.
maxonik [38]
The formula is

F_grav = G * m1 * m2 / r^2

G m1 and m2 are going to stay the same once chosen no matter what the distance is. The only thing that will change is the distance.

As the distance increases, the Gravitational Force will decrease. It will decrease by quite a bit.

As the distance decreases, the gravitational force will Increase.

The relationship is inverse. The moon travelling around the earth is one example. The earth travelling around the sun is another.
8 0
3 years ago
What is Biomass?<br> What is Biofuel?<br> Please help me science students
kramer

Answer:

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7 0
2 years ago
A 46.0-kg box is being pushed a distance of 8.80 m across the floor by a force P whose magnitude is 171 N. The force P is parall
dolphi86 [110]

Answer:

a) 1504.8 J

b) 991.76 J

c) 0J

d) 0J

Explanation:

(a) The work done by the force P on the box is given by the following formula:

W_P=Px

P: applied force = 171N

x: distance in which the for P is applied = 8.80m

you replace the values of P and x and obtain:

W_P=(171N)(8.80m)=1504.8J

(b) The work don by the friction force is:

W_f=F_fx=\mu N x=\mu Mg x

μ = coefficient of kinetic friction = 0.250

M: mass of the box = 46.0kg

g: gravitational constant = 9.8 m/s^2

W_f=(0.250)(46.0kg)(9.8m/s^2)(8.80m)=991.76J

(c) The Normal force is

N=Mg=(46.0kg)(9,8m/s^2)=450.8N

but this force does not do work on the box because the direction is perpendicular to the direction of the force P.

W_N=0J

(d) the same as before:

W_g=0J

8 0
3 years ago
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