A woman takes her dog rover for a walk on a leash. She pulls on the leash with a force of 30.0 N at an angle of 29° above the ho
1 answer:
19.8 N force is tending to lift Rover vertically off the ground.
<h3>What is horizontal and vertical component?</h3>The horizontal velocity component () describes the influence of the velocity in displacing the projectile horizontally. The vertical velocity component (
) describes the influence of the velocity in displacing the projectile vertically.
According to the question,
The women pulls the dog with a force of 30 N at an angle of 29° from the horizontal.
Horizontal component= 30cos(29°) = 22.2 N
Vertical component = 30sin(29°) = 19.8 N
Therefore,
The horizontal component would tend to make the dog move forward and the vertical component would tend lift it off the ground.
Hence,
19.8 N force is tending to lift Rover vertically off the ground.
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Answer:
The maximum wavelength of light that could liberate electrons from the aluminum metal is 303.7 nm
Explanation:
Given;
wavelength of the UV light, λ = 248 nm = 248 x 10⁻⁹ m
maximum kinetic energy of the ejected electron, K.E = 0.92 eV
let the work function of the aluminum metal = Ф
Apply photoelectric equation:
E = K.E + Ф
Where;
Ф is the minimum energy needed to eject electron the aluminum metal
E is the energy of the incident light
The energy of the incident light is calculated as follows;
The work function of the aluminum metal is calculated as;
Ф = E - K.E
Ф = 8.02 x 10⁻¹⁹ - (0.92 x 1.602 x 10⁻¹⁹)
Ф = 8.02 x 10⁻¹⁹ J - 1.474 x 10⁻¹⁹ J
Ф = 6.546 x 10⁻¹⁹ J
The maximum wavelength of light that could liberate electrons from the aluminum metal is calculated as;
So this is the info that's given to us:
m1 = 4.87 x 10^24 kg
m2 = 4.87 x 10^24kg
F = 2.58 x 10^3 N
Now we can use this equation to solve:
You may be asking what g is. Well, it is equal to 6.67x10^-11 m3 /kg s2. G is gravitational constant. So :
As you can see we only have one variable, so we solve for r!
I hope this helps you out. I remember when I was first learning Newton's law<span> of universal </span><span>gravitation and I had some trouble. But with some practice, I got better. =) </span>
m1 = 4.87 x 10^24 kg
m2 = 4.87 x 10^24kg
F = 2.58 x 10^3 N
Now we can use this equation to solve:
You may be asking what g is. Well, it is equal to 6.67x10^-11 m3 /kg s2. G is gravitational constant. So :
As you can see we only have one variable, so we solve for r!
I hope this helps you out. I remember when I was first learning Newton's law<span> of universal </span><span>gravitation and I had some trouble. But with some practice, I got better. =) </span>