Answer: A
si, di, are expressed as negative and f is expressed as positive values.
Explanation:
When the object is located at a location in front of the focal point of a convex len, the image will always be located somewhere on the same side of the lens as the object. The image is located behind the object. In this case, the image will be an upright image and the image is enlarged
In this question, the relationship between the focal length, image distance di and object distance is
I/f = 1/di + 1/do that is
I/f - 1/di - 1/do = 0
The image size si is also negative since the image is a virtual image.
Therefore, si, di, are expressed as negative, f is expressed as positive values.
