A = Delta v/Delta t
Delta v = 25 - 0 = 25
Delta t = 30
25/30 = 5/6 = 1.66 repeating
There is no temperature change which drives heat flow, thus no heat will be released by the water.
<h3>
Heat released by the water when it freezes</h3>
The heat released by the water when it freezes is calculated as follows;
Q = mcΔФ
where;
- m is mass of water
- c is specific heat capacity of water
- ΔФ is change in temperature = Фf - Фi
Initial temperature of water, Фi = 0 °C
when water freezes, the final temperature, Фf = 0 °C
Q = 22 x 4200 x (0 - 0)
Q = 0
Since there is no temperature change which drives heat flow, thus no heat will be released by the water.
Learn more about heat flow here: brainly.com/question/14437874
Are breathing hard. This is because cardiovascular exercise makes the heart beat faster which in turn creates a need for more air.
Answer:
- magnitude : 1635.43 m
- Angle: 130°28'20'' north of east
Explanation:
First, we will find the Cartesian Representation of the 
and 
vectors. We can do this, using the formula
where 
its the magnitude of the vector and θ the angle. For we have:
where the unit vector 
points east, and 
points north. Now, the will be:
Now, taking the sum:
This is
Now, for the magnitude, we just have to take its length:
For its angle, as the vector lays in the second quadrant, we can use:
Answer:
Explanation:
efficiency of carnot engine operating between 1100 K and 320 K
= 1100 - 320 / 1100
= .709
efficiency of heat engine = 120 / 400 = .30
2 nd law thermal efficiency of heat engine = .30 x 100 / .709
= 42.31 % .
