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padilas [110]
2 years ago
8

An unknown material has a mass of 2.75 g and a volume of 4 cm3. What is the density of the material? Round to the nearest tenth.

Physics
2 answers:
NemiM [27]2 years ago
8 0
The density of a material is given by:
d= \frac{m}{V}
where
d is the density
m is the mass of the sample
V is its volume

In our problem, the material has a mass of m=2.75 g and a volume of V=4 cm^3, so its density is:
d= \frac{m}{V}= \frac{2.75 g}{4 cm^3}=0.69 g/cm^3=0.7 g/cm^3

So, the correct answer is D).
Ksivusya [100]2 years ago
8 0

The density of the material is 0.7 \mathrm{g} / \mathrm{cm}^{3}

Answer: Option D

<u>Explanation:</u>

Density of any material is defined as the amount of mass present in a specified volume. So density is directly proportional to the mass of the object and inversely proportional to the volume in which the mass is present.

So the density will be calculated as the ratio of mass to the volume. Thus as the mass of the unknown materials is given as 2.75 g present in a volume of 4 \mathrm{cm}^{3}, the density will be

         \text { Density }=\frac{\text {Mass}}{\text {Volume}}

Thus,

       \text { Density }=\frac{2.75}{4}=0.7 \mathrm{g} / \mathrm{cm}^{3}

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Andreyy89
Below are the choices that can be found elsewhere:

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</span>
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<span>Ga (s) --> Ga (g) delta H = 277 kJ/mol </span>

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<span>Ga (s) --> Ga (l) delta H = 6 kJ/mol </span>

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<span>*ANSWER* </span>
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3 years ago
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7 0
2 years ago
Julian tests four springs and records the results in the table
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Answer:

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Explanation:

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Magnitude of Force applied on the spring is given by,

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Magnitude of Force applied on the spring is given by,

F = k x

Where, F = force applied

k = spring constant

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k = F/x

k = 60 / 0.3

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Spring Y:

Magnitude of Force applied on the spring is given by,

F = k x

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Magnitude of Force applied on the spring is given by,

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Thus, list of spring in order of increasing spring constant is given by,

W, Y, X, Z





8 0
3 years ago
Read 2 more answers
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