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Tamiku [17]
4 years ago
9

A box is sliding up an incline that makes an angle of 14.0° with respect to the horizontal. the coefficient of kinetic friction

between the box and the surface of the incline is 0.180. the initial speed of the box at the bottom of the incline is 2.20 m/s. how far does the box travel along the incline before coming to rest?
Physics
1 answer:
mezya [45]4 years ago
6 0
A box is sliding up an incline that makes an angle of 14.0° with respect to the horizontal. the coefficient of kinetic friction between the box and the surface of the incline is 0.180. the initial speed of the box at the bottom of the incline is 2.20 m/s. how far does the box travel along the incline before coming to rest?
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What is the information gathered in a scientific investigation called
Alika [10]
<span>the information gathered in a scientific investigation is called : Data
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3 years ago
Two particles are located on the x axis. particle 1 has a mass m and is at the origin. particle 2 has a mass 2m and is at x = +l
wlad13 [49]

The solution would be like this for this specific problem:

<span>
The force on m is:</span>

<span>
GMm / x^2 + Gm(2m) / L^2 = 2[Gm (2m) / L^2] -> 1

The force on 2m is:</span>

<span>
GM(2m) / (L - x)^2 + Gm(2m) / L^2 = 2[Gm (2m) / L^2] -> 2

From (1), you’ll get M = 2mx^2 / L^2 and from (2) you get M = m(L - x)^2 / L^2 

Since the Ms are the same, then 

2mx^2 / L^2 = m(L - x)^2 / L^2 

2x^2 = (L - x)^2 

xsqrt2 = L - x 

x(1 + sqrt2) = L 

x = L / (sqrt2 + 1) From here, we rationalize. 

x = L(sqrt2 - 1) / (sqrt2 + 1)(sqrt2 - 1) 

x = L(sqrt2 - 1) / (2 - 1) 


x = L(sqrt2 - 1) </span>

 

= 0.414L

 

<span>Therefore, the third particle should be located the 0.414L x axis so that the magnitude of the gravitational force on both particle 1 and particle 2 doubles.</span>

8 0
4 years ago
Predict what would happen if earth’s plates stopped moving.
Hatshy [7]
We would have earthquakes and tsunamis, i think, i don't really know?!?
4 0
3 years ago
You have just landed on Planet X. You take out a 100-g ball, release it from rest from a height of 10.0 m, and measure that it t
Nina [5.8K]

Answer:

Weight in planet X = 0.413 N

Explanation:

Weight = Mass x Acceleration due to gravity.

W = mg

Mass, m = 100 g = 0.1 kg

We have equation of motion s = ut + 0.5 at²

Displacement, s = 10 m

Initial velocity, u = 0 m/s

Time, t = 2.2 s

Substituting

        s = ut + 0.5 at²

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        a = 4.13 m/s²

Acceleration due to gravity, a = 4.13 m/s²

W = mg = 0.1 x 4.13 = 0.413 N

Weight in planet X = 0.413 N

5 0
3 years ago
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