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Anna [14]
2 years ago
10

When hydrated copper(II) sulfate crystals are heated, anhydrous copper(II) sulfate forms. A mass of 12.5 g of hydrated copper(II

) sulfate crystals is heated in a crucible until all the water of crystallisation is removed.
A mass of 8.0 g of anhydrous copper(II) sulfate forms.
Calculate the formula of hydrated copper(II) sulfate CuSO4.nH2O
Show your working.
[Mr of CuSO4 = 159.5 Mr of H2O = 18]
Mass of water = g
Water of crystallization (n) =
Formula of hydrated copper(II) sulfate =
Chemistry
1 answer:
pychu [463]2 years ago
7 0

The formula of hydrated copper(II) sulfate is CuSO4.10H2O

<h3>What is the formula of the hydrated copper (ii) sulfate salt?</h3>

The formula of the hydrated copper (ii) sulfate is determined as follows:

Mass of hydrated salt = 12.5 g

Mass of anhydrous salt = 8.0 g

Mass of water = 12.5 - 8 = 4.5 g

mole ratio of water and anhydrous salt is;

4.5/18 : 8.0/159.5

0.562 : 0.05

10 : 1

Water of crystallization (n) = 10.

Therefore, the formula of hydrated copper(II) sulfate is CuSO4.10H2O

Learn more about water of crystallization at: brainly.com/question/26146814

#SPJ1

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Part 1: A cylinder containing 20.0 L of compressed nitrogen is connected to an empty (evacuated) vessel with an unknown volume.
baherus [9]

Answer:

The volume of the vessel is 250 L

Partial pressure of hydrogen = 189 torr

Explanation:

Using Boyle's law  

{P_1}\times {V_1}={P_2}\times {V_2}

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Using above equation as:

{P_1}\times {V_1}={P_2}\times {V_2}

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According to Dalton's law of partial pressure:-

P_{H_2}=Mole\ fraction\times Total\ Pressure

So, according to definition of mole fraction:

Mole\ fraction\ of\ H_2=\frac {n_{H_2}}{n_{H_2}+n_{He}}

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7 0
3 years ago
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Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we do not include the spectator ions in the equations.

When hydrochloric acid react with potassium cyanide, then it gives potassium chloride and hydrocyanic acid as products.

The complete ionic equation will be:

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