Answer:
It should be B
Explanation:
because I just searched it up if I'm wrong I'm wrong
Answer is: Ksp for magnesium hydroxide is 1,1·10⁻¹¹.<span>
Chemical reaction: Mg(OH)</span>₂(s) → Mg²⁺(aq) + 2OH⁻(aq).
s(Mg(OH)₂) = 1,4·10⁻⁴ M.
s(Mg(OH)₂) = s(Mg²⁺).
s(OH⁻) = 2s(Mg(OH)₂).
Ksp = s(Mg²⁺) · (s(OH⁻))².
Ksp = 1,4·10⁻⁴ M · (2,8·10⁻⁴ M)².
Ksp = 1,1·10⁻¹¹.
Answer:
<em><u>A. any absorbance of light by the solvent AND the cuvette needs to be accounted for</u></em>
Explanation:
Blank calibrations are usually carried out on the spectrometer to eliminate and account for any readings that would come from absorptions of the curvette, solvents/reagents or anything that is not the main analyte we are testing for.
Hence the blank solution does not contain the analyte itself. Fingerprints should be removed from the curvette as practice. Hence the most suitable answer amongst the options is A.
I hope this was clear ad most of all, helpful.
Yes as there is advertisements for this as a alternative to glue.<span />
<h2>
</h2>
Explanation:
- Atomic number of krypton [Kr] =36
- Electronic configuration of krypton [Kr] = [Ar]
- Common ions with valence electronic configuration of [Kr] are bromine ion, strontium ion, selenite ion and rubidium ion.
- The Atomic number of the following ions in increasing order are;
Se < Br < Rb < Sr
Se (Z) = 34
Br (Z) = 35
Rb (Z) = 37
Sr (Z) = 38
- Electronic configuration of the following elements are:
Se (Z) = [Ar]
Br (Z) = [Ar]
Rb (Z) = [Kr]
Sr (Z) = [Kr]
Therefore, the respective ions formed according to theabove electronic configuration are
Hence the two anions are
and, the two cations are