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CaHeK987 [17]
3 years ago
10

Discussion Questions 1. Given the equilibrium equation for a general reaction, A + B  C + D, explain what happens to the reacta

nts and products from time 0 until the time at which the reaction reaches equilibrium. 2. Given this reaction at equilibrium, C(s) + CO2(g)  2CO(g) (∆H° = 119kJ), explain the changes that would occur when the following stresses are applied or removed for this reaction. (a) CO is removed. (b) Heat is added. (c) CO2 is added. (d) Heat is removed.
Chemistry
1 answer:
ANTONII [103]3 years ago
8 0

Answer:The equilibrium constant for a given reaction is [concentration of products]/[concentration of reactants].

Explanation:

Equilibrium constant=[concentration of products]/[concentration of reactants]

The concentration of reactant  molecules is maximum at time 0 and it  decreases as the reaction proceeds, The concentration of product molecules increases.At equilibrium the concentration of reactants and products are equal.

All the changes would occur in accordance with the LeChateliers principle.

For the given reaction the following changes would occur:

a When CO is removed from the reaction mixture so the reaction would shift towards right that is in forward direction as we are decreasing the concentration of CO so the system would try to increase the concentration of CO and that can happen by more production of CO.

b Since the above reaction is an endothermic reaction so when we would be adding heat to the system that is when we would increase the temperature  the reaction would shift forwards as  more heat energy is absorbed by reactants  to form more products.

c When more CO₂ is added so more amount of reactants are added to the system so the system would try to decrease the amount of reactants that is CO₂ and hence more amount of products would be formed.The reaction would shift in forward direction.

d Since  this reaction is endothermic in nature so when we remove the heat from reaction hence even less amount of heat is present in the system and so the reaction shift in backward direction as the reaction cannot proceed without enough amount of heat.

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How many grams of oxygen are produced when 7.65 moles of water is decomposed
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Answer:

The answer to your question is 122.4 g of O₂

Explanation:

Data

mass of O₂ = ?

moles of H₂O = 7.65

Process

1.- Write the balanced chemical reaction

                   2H₂O  ⇒  2H₂  +  O₂

2.- Convert the moles of H₂O to grams

molar mass of H₂O = 2 + 16 = 18 g

                    18 g of H₂O ---------------- 1 mol

                      x                ----------------- 7.65 moles

                      x = (7.65 x 18) / 1

                      x = 137.7 g H₂O

3.- Calculate the grams of O₂

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              137.7 g of H₂O -------------------  x

                        x = (32 x 137.7) / 36

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Answer:

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Explanation:

Using Ideal gas equation for same mole of gas as

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Given ,  

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Using above equation as:

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

\frac {{9}\times {21}}{253}=\frac {{15}\times {V_2}}{302}

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3 years ago
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