Question

An archer pulls her bowstring back 0.400 m by exerting a force that increases uniformly from zero to 230 N. (a) What is the equivalent spring constant of the bow

Answer 1

Answer: An archer pulls her bowstring back 0.400m by exerting a force that increases uniformly from zero to 230N. The equivalent spring constant of the bow will be 575N/m

Explanation: To find the answer, we have to know about the Simple Harmonic Motion.

What is Simple Harmonic Motion?

• A particle is said to execute simple harmonic motion, if it moves to and fro about mean position under the action of restoring force.
• The restoring force is directly proportional to its displacement from the mean position and always directed towards the mean position.
• If x is the displacement from the mean position, and F is the restoring force, then

                   $F$∝$-x$

                   $F=-kx$ where, k is called the spring constant.

How to approach the problem?

• Given that, an archer pulls her bowstring back 0.400m by exerting a force that increasing from zero to 230N.
• Here, from the question given, we can write, $x=-0.400m$ and $F=230N$.
• Thus, our spring constant k will be,

                       $k=-F/x= (230)/ (0.400) =575 N/m.$

Thus, we can conclude that, the equivalent spring constant of the bow will be 575N/m.

Learn more about the Simple Harmonic Motion here:

brainly.com/question/28019840

#SPJ4