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slava [35]
3 years ago
12

The spectrum of a distant star shows that one in 2 e6 of the atoms of a particular element is in its first excited state 7.5 eV

above the ground state. What is the temperature of the star? (You can ignore the other excited states and assume the ratio of statistical weights is 4
Physics
1 answer:
Alchen [17]3 years ago
5 0

Answer:

The temperature of star is 5473.87 K

Explanation:

Given:

Energy difference \Delta E = 7.5 eV

The ratio of number of particle \frac{N_{f} }{N_{i} } = \frac{1}{2 \times 10^{6} }

Degeneracy ratio \frac{g_{f} }{g_{i} }  = 4

From the formula of boltzmann distribution for population levels,

     \frac{N_{f} }{N_{i} } =\frac{g_{f} }{g_{i} }  e^{-\frac{\Delta E}{kT} }

Where k = boltzmann constant = 8.62 \times 10^{-5} \frac{eV}{K}

     \frac{1}{2 \times 10^{6} } =4  e^{-\frac{7.5 eV}{8.62 \times 10^{-5} T} }

  8 \times 10^{6} } = e^{\frac{7.5 eV}{8.62 \times 10^{-5} T} }

\ln(8 \times 10^{6})  = {\frac{7.5 eV}{8.62 \times 10^{-5} T} }

  T  = {\frac{7.5 eV}{8.62 \times 10^{-5} \ln(8 \times 10^{6})} }

  T = 5473.87 K

Therefore, the temperature of star is 5473.87 K

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B

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A 24 kg child sits on a 2.0-m-long rope swing. You are going to give the child a small, brief push at regular intervals.
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time should you wait between pushes is 2.83 sec.

the question is incomplete, full statement is-

A 24 kg child sits on a 2.0-m-long rope swing. You are going to give the child a small, brief push at regular intervals. If you want to increase the amplitude of her motion as quickly as possible, how much time should you wait between pushes?

<h3>What is Amplitude?</h3>

In physics, amplitude refers to the greatest displacement or distance that a point on a vibrating body or wave may move relative to its equilibrium location. It is equivalent to the vibration path's half-length.

regular interval - at similarly spaced intervals: having the same interval of time between occurrences From 4 a.m. to midnight, the buses operate at regular intervals. The boards are positioned at regular intervals, with an equal amount of space between each.

The length of swing, l = 2.1 m

The time between the pushes is nothing but the Time period

and is given by the formula,

T = 2\pi  ( \frac{l}{g}  )^{\frac{1}{2} }

= 2 * 3.14 ( 2.0/ 9.8 ) ^ (1/2)

= 2.83 sec

to learn more about Amplitude go to - brainly.com/question/3613222

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