Ask question

Ask question

All categories

Free_Kalibri [48]

2 years ago

15

How much horsepower is produced by 2023 z’s 3. 0-liter twin-turbo 6-cylinder engine?.

1 answer:

garri49 [273]2 years ago

6 0

400 horsepower is produced by 2023 z's 3. 0-liter twin-turbo 6-cylinder engine.

<h3>What is horsepower?</h3>

The power an engine produced is referred to as horsepower. In the British Imperial System, one horsepower equals 33,000 foot-pounds of work per minute, i.e., the force required to lift a mass of 33,000 pounds off the ground in a single motion for one minute.

The new Z's 3.0-liter twin-turbo V6 engine produces 400 horsepower and 350 pound-feet of torque. This is 68 horsepower and 80 lb-ft more than the previous 370Z. The 6-speed manual transmission that comes standard or the optional 9-speed automatic transmission with paddle shifters are both paired with this one engine option.

Learn more about horsepower here:

brainly.com/question/17918928

#SPJ4

You might be interested in

Read the given list of organisms.

Nadya [2.5K]

They are all herbivores

3 0

3 years ago

Read 2 more answers

What does the Nucleolus do?

SCORPION-xisa [38]

Answer:

C

Explanation:

6 0

3 years ago

Read 2 more answers

A 70-kg boy is sitting 3 m from the ground in a tree. What is his gravitational potential energy

steposvetlana [31]

m x h x 9.8 m/s squared

70 kg x 3 m x 9.8 m/s squared= 2058 Joules

7 0

4 years ago

Guys please help me

Likurg_2 [28]

Answer:

1) $t=2.26\: s$

2) $S=33.9\: m$

3) $v=26.77\: m/s$

4) $\alpha=55.92$

Explanation:

1)

We can use the following equation:

$y_{f}=y_{0}+v_{iy}t-0.5*g*t^{2}$

Here, the initial velocity in the y-direction is zero, the final y position is zero and the initial y position is 25 m.

$0=25-0.5*9.81*t^{2}$

$t=2.26\: s$

2)

The equation of the motion in the x-direction is:

$v_{ix}=\frac{S}{t}$

$15=\frac{S}{2.26}$

$S=33.9\: m$

3)

The velocity in the y-direction of the stone will be:

$v_{fy}=v_{iy}-gt$

$v_{fy}=0-(9.81*2.26)$

$v_{fy}=-22.17\: m/s$

Now, the velocity in the x-direction is 15 m/s then the velocity will be:

$v=\sqrt{v_{x}^{2}+v_{fy}^{2}}=\sqrt{15^{2}+(-22.17)^{2}}$

$v=26.77\: m/s$

4)

The angle of this velocity is:

$tan(\alpha)=\frac{22.17}{15}$

$\alpha=tan^{-1}(\frac{22.17}{15})$

$\alpha=55.92$

Then α=55.92° negative from the x-direction.

I hope it helps you!

6 0

3 years ago

How would i solve these problems, nobody in my class understands and there is a substitute

drek231 [11]

find acceleration force divided by Mass

a=f/m

6 0

4 years ago