Answer:
(a). The distance is 49.79 m.
(b). The speed of the ball is 24.39 m/s.
Explanation:
Given that,
Speed = 20 m/s
Angle = 40°
Height = 22 m
Time = 3.25 sec
(a). We need to calculate the distance
Using formula of distance

Put the value into the formula


(b). We need to calculate the horizontal velocity
Using formula of velocity

Put the value into the formula


We need to calculate the vertical velocity
Using equation of motion

Put the value into the formula


Negative sign shows the opposite direction.
We need to calculate the speed of ball
Using formula of speed



Hence, (a). The distance is 49.79 m.
(b). The speed of the ball is 24.39 m/s.
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Answer:
Maximum height, h = 1.74 meters
Explanation:
It is given that,
A potato is shot out of the cylinder. It is a case of projectile motion. The potato makes an angle of 17 degrees above the horizontal.
Initial speed with which the potato is shot out, u = 20 m/s
We have to find the maximum height of the potato. The maximum height of a projectile (h) is given by the following formula as :

Where
= angle between the projectile and the surface
g = acceleration due to gravity

h = 1.74 m
or h = 1.74 meters
Hence, this is the required solution.
The wavelength of the note is

. Since the speed of the wave is the speed of sound,

, the frequency of the note is

Then, we know that the frequency of a vibrating string is related to the tension T of the string and its length L by

where

is the linear mass density of our string.
Using the value of the tension, T=160 N, and the frequency we just found, we can calculate the length of the string, L:
Answer:
Explanation:
Givens
vi = 10 m/s
a = 1.5 m/s^2
d = 600 m
vf = ?
Formula
vf^2 = vi^2 + 2*a*d
Solution
vf^2 = 10^2 + 2*1.5 * 600
vf^2 = 100 + 1800
vf^2 = 1900
sqrt(vf^2) = sqrt(1900)
vf = 43.59 m/s