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bagirrra123 [75]
2 years ago
12

A weather forecaster uses Doppler radar to predict the track of a storm near the town of hillville when the Doppler signal is he

pointed at the storm from the town center the frequency of the waves appear to be increasing what should the weather forecaster predict?
A. That the storm will move around the edges of hillville without hitting the towns center

B. That the storm is moving toward hillville and that residents should be prepared

C. That the storm will not hit hillville because it is moving away

D. That residents should be prepared because it is impossible to know whether the storm will hit
Physics
1 answer:
Veseljchak [2.6K]2 years ago
6 0

Answer: That the storm is moving toward hillville and that residents should be prepared.

Explanation:

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Doss [256]

Answer:

A magnet is used in a compass to show the direction.

Magnets are used in medical equipment.

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5 0
1 year ago
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A bicycle tire is spinning counterclockwise at 2.70 rad/s. During a time period Δt = 1.50 s, the tire is stopped and spun in the
Andru [333]

Answer:

Δω = -5.4 rad/s

αav = -3.6 rad/s²

Explanation:

<u>Given</u>:

           Initial angular velocity = ωi = 2.70 rad/s

           Final angular velocity = ωf = -2.70 rad/s (negative sign is  

           due to the movement in opposite direction)

           Change in time period = Δt = 1.50 s

<u>Required</u>:

           Change in angular velocity = Δω = ?

           Average angular acceleration = αav = ?

<u>Solution</u>:

          <u>Angular velocity (Δω):</u>

               Δω = ωf - ωi

               Δω = -2.70 - 2.70

               Δω = -5.4 rad/s.

          <u> Average angular acceleration (αav):</u>

               αav = Δω/Δt

               αav = -5.4/1.50

              αav = -3.6 rad/s²

Since, the angular velocity is decreasing from 2.70 rad/s (in counter clockwise direction) to rest and then to -2.70 rad/s (in clockwise direction) so, the change in angular velocity is negative.

7 0
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8 0
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This is simple as power in watts is equal to joules per second so we can do 1500 joules divided by 30 seconds which equals 50 watts
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