1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Paladinen [302]
2 years ago
10

An infinitely long line charge of uniform linear charge density λ = -3.00 µC/m lies parallel to the y axis at x = -3.00 m. A poi

nt charge of 3.00 µC is located at x = 1.00 m, y = 2.00 m. Find the electric field at x = 2.00 m, y = 1.50 m.
Physics
1 answer:
liq [111]2 years ago
7 0

Answer:

E=[8.1X-9.63Y]*10^{3}N/m

Explanation:

Field in the point is the sum of the point charge electric field and the field of the infinite line.

First, we calculate the point charge field:

E_{Charge}=\frac{1}{4\pi \epsilon_0}  *\frac{Q}{||r_p -r||^2} *Unitary vector\\||r_p -r||^2=(x_p-x)^2+(y_p -y)^2=1.25 m^2\\Unitary Vector=\frac{(r_p -r)}{||r_p -r||}=\frac{(x_p-x)X+(y_p -y)Y}{||r_p -r||}\\=\frac{2\sqrt{5} }{5}X- \frac{\sqrt{5} }{5}Y \\E_{Charge}=K*\frac{3\mu C}{1.25m^2}*(\frac{2\sqrt{5} }{5}X- \frac{\sqrt{5} }{5}Y)

It is vectorial, where <em>X</em> and <em>Y</em> represent unitary vectors in <em>X</em> and <em>Y</em>. we recall the Coulomb constant <em>k=</em>\frac{1}{4\pi \epsilon_0} and not replace it yet. Now we compute the line field as follows:

E_{Line}=\frac{\lambda}{2\pi \epsilon_0 distance} *Unitary Vector\\Unitary Vector=X (The field is only in the perpendicular direction to the wire, which is X)

E_{Line}=\frac{-3\mu C/m*2}{2*2\pi \epsilon_0 5*m}X=K*\frac{6\mu C/m}{ 5*m}(-X)

We multiplied by 2/2 in order to obtain Coulomb constant and express it that way. Finally, we proceed to sum the fields.

E=K*\frac{3\mu C}{1.25m^2}*(\frac{2\sqrt{5} }{5}X- \frac{\sqrt{5} }{5}Y)+K*\frac{6\mu C}{ 5*m^2}(-X)\\E=K*[2.15-1.2]X-K*[1.07]Y \mu N/m\\E=K*[0.9X-1.07Y] \mu C/m^2\\E=[8.1X-9.63Y]*10^{3}N/m

You might be interested in
You venture out on a cold winter morning to warm up your vehicle. You have layers of cotton/polyester blend clothes on and from
xxMikexx [17]

Answer:

There is a localization of negative charge near the door handle.

4 0
2 years ago
Please Help Me
JulijaS [17]

1. a=Δv/Δt=(v-vo)/t=(0-25)/5=-25/5=-5 m/s²

The "-" sign shows us that the car has a slow motion


2.a=Δv/Δt=(v-vo)/t=(10-0)/4=10/4=2,5 m/s²


3.they do not have acceleration because they go at constant speed


7 0
3 years ago
what is the acceleration of a 2,000- kilogram truck if a force of 4,200. N is used to make it start moving forward?
cupoosta [38]

Newton's 2nd law of motion:              Force = (mass) x (acceleration)

Divide each side by (mass) :              Acceleration = (force) / (mass)

       Acceleration of the truck = (4,200 N) / (2,000 kg) = 2.1 m/s²

5 0
3 years ago
An unknown mass of each substance, initially at 25.0 ∘C, absorbs 1920 J of heat. The final temperature is recorded. Find the mas
zhannawk [14.2K]

Answer: mass for Pyrex glass 84.21g

mass for sand 61.6g

mass for ethanol 41.32g

mass for water 62.07g

Explanation

By definition specific heat is the amount of heat required to change the temperature of 1 kg mas by 1°C

Q=mcΔT is formula for specific heat

Q is heat transfer

m is mass

ΔT is change in temperature

c   is specific heat

c of Pyrex glass= 0.75 j/g°C

c of sand = 0.84 j/g°C

c of ethanol= 2.42 j/g°C

c of water = 4.18 j/g°C

now we will make M(mass) the subject, so equation becomes

m=Q/cΔT

for

pyrex glass T<em>f=</em>55.4°C

m=1920/(55.4-25)*0.75

m=84.21g {after cutting J(joules) and °C we are left with g(grams)}

for

sand T<em>f</em>=62.1°C

m=1920/(62.1-25)*0.84

m=61.6g {after cutting J(joules) and °C we are left with g(grams)}

for

ethanol T<em>f</em>=44.2°C

m=1920/(44.2-25)*2.42

m=41.32g  {after cutting J(joules) and °C we are left with g(grams)}

for

water T<em>f=</em>32.4°

m=1920/(32.4-25)*4.18

m=62.07g  {after cutting J(joules) and °C we are left with g(grams)}

i hope you understand the solution, thank you.

7 0
2 years ago
Social loafing is most likely to occur _____.
loris [4]

Answer:

Answer is when no single person in a group is being watched.

Refer below.

Explanation:

Social loafing is most likely to occur:

when no single person in a group is being watched.

5 0
3 years ago
Other questions:
  • The circuit below represents a _ circuit<br> .Series<br> .Micro<br> .Parallel<br> .Complex
    15·1 answer
  • The equipotential surfaces surrounding a point charge are concentric spheres with the charge at the center. If the electric pote
    9·1 answer
  • a 25 newton force applied on an object moves it 50 meters. the angle between the force and displacement is 40.0°. what is the va
    14·1 answer
  • Crude oil is a mixture of many different components. The extraction of crude oil from the Earth is important, but its refinement
    10·1 answer
  • An object of 4 cm length is placed at a distance of 18 cm in front of a convex mirror of radius of curvature 30 cm. Find the pos
    7·1 answer
  • PLZ HELPPPPP!! i'll give brainliest
    5·1 answer
  • Artificial satellites in space can help you find locations on<br> Earth. True or false?
    10·1 answer
  • A ball rolls across the floor at a constant speed, what will happen to it if there is no friction?
    12·1 answer
  • How can I shorten this and for it to sill make sense?
    9·2 answers
  • Plz help!!!!! Due tomorrow Analyze the weather map in 2 to 3 complete sentences. Describe what the weather will be in Olympia, W
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!