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3 years ago

Please answer the following essay question:

Physics

1 answer:

g100num [7]3 years ago

5 0

Explanation:

The atoms of elements such as hydrogen, sodium and potassium have only one electron in their outermost electron shell while atoms such as calcium, iron and chromium have several loosely held electrons. The bond would be almost entirely covalent. Ionic bonds form between atoms of very different electronegativities, e.g. sodium and chlorine, in which case the electron is largely removed from the sodium atom and transferred to the chlorine atom, resulting in sodium(+) chloride(-) ionic bonding

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This is a problem about a child pushing a stack of two blocks along a horizontal floor. The masses of the blocks, and the coeffi

Rufina [12.5K]

Answer:

N = 23.4 N

Explanation:

After reading that long sentence, let's solve the question

The contact force is the so-called normal in this case we can find it by writing the translational equilibrium equation for the y axis

N - w₁ -w₂ =

N = m₁ g + m₂ g

N = g (m₁ + m₂)

let's calculate

N = 9.8 (0.760 + 1.630)

N = 23.4 N

This is the force of the support of the two blocks on the surface.

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3 years ago

an object is moving forward with a constant velocity. which statement about this object must be true?

love history [14]

Answer:

• Its acceleration is zero

Explanation:

from definition of acceleration:

${ \rm{acceleration = \frac{change \: in \: velocity}{time} }} \\ \\ { \rm{acceleration = \frac{ \delta \: (velocity)}{time} }}$

• since velocity is constant, change in velocity is zero

${ \boxed{ \rm{ \delta \: (velocity) = 0}}}$

• therefore:

${ \rm{acceleration = \frac{0}{time} }} \\ \\ { \boxed{ \tt{acceleration = 0 \: m {s}^{ - 2} }}}$

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3 years ago

Derive velocity-time relation from velocity-time graph

Brrunno [24]

Explanation:

hope this helps you

.....,.......

7 0

3 years ago

Connie teaches her children to call adults "sir" and "ma'am" and to say "please" and "thank you." These rituals are known as

Nat2105 [25]

Manners. they are known as manners.

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3 years ago

Determine the energy required to accelerate an electron from (a) 0.500c to 0.900c and (b) 0.900c to 0.990c

Lera25 [3.4K]

Answer:

0.582 MeV

2.45 MeV

Explanation:

$E_r=0.511\ MeV$ =Electron rest energy

(a) 0.500c to 0.900c

$W=\left(\frac{1}{\sqrt{1-\frac{v_f^2}{c^2}}}-\frac{1}{\sqrt{1-\frac{v_i^2}{c^2}}}\right)E_r\\\Rightarrow W=\left(\frac{1}{\sqrt{1-0.9^2}}-\frac{1}{\sqrt{1-0.5^2}}\right)0.511\\\Rightarrow W=0.582\ MeV$

Energy required is 0.582 MeV

(b) 0.900c to 0.990c

$W=\left(\frac{1}{\sqrt{1-\frac{v_f^2}{c^2}}}-\frac{1}{\sqrt{1-\frac{v_i^2}{c^2}}}\right)E_r\\\Rightarrow W=\left(\frac{1}{\sqrt{1-0.99^2}}-\frac{1}{\sqrt{1-0.9^2}}\right)0.511\\\Rightarrow W=2.45\ MeV$

Energy required is 2.45 MeV

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3 years ago