Answer:
The correct answer is C
Explanation:
In this exercise you are asked to analyze the following situation: for a fixed observer, the two balloons are launched at the same time.
If the observer is mobile moving towards the positive side of axis ax we have several
possibilities when starting the movement
* the observer is to the left of the two balloons
* the observer is between the two balloons
* the observer is to the right of the two baloomls
The time it takes for the signal to arrive to know which ball goes first is
v = d / t
t = d / v
If the signal goes at the speed of light, the speed is a constant and the time will depend only on the distance, so we see that the trigger changes depending on the relative position between a given ball and the observer.
Consequently, it will be seen which comes out first, depending on the relative position with the observer.
The correct answer is C
Answer:
solar nebula, the sun, planetesimals, inner planets, and last but not least outer planets
The electric field at point A located 2.00 mm above the dipole's midpoint is 5.287 X 10¹³ N/C.
<h3>
Electric field of the positive particle</h3>
The electric field is calculated as follows;
E = kq/r²
where;
- r is the distance between the charges
- k is Coulomb's constant
- q is magnitude of the charge
midpoint of 3.08 m, x = 1.54 mm
r(1.54 mm, 2.00 mm)
|r| = √(1.54² + 2²)
|r| = 2.52 mm
E = (9 x 10⁹ x 37.3 x 10⁻³)/(2.52 x 10⁻³)²
E = 5.287 X 10¹³ N/C
Thus, the electric field at point A located 2.00 mm above the dipole's midpoint is 5.287 X 10¹³ N/C.
Learn more about electric field here: brainly.com/question/14372859
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Question three is C and question 4 is b
Answer:
that is preatty balenced m8
Explanation:
