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Andrei [34K]
3 years ago
13

What is the conclusion of coin and feather experiment? ​

Physics
1 answer:
valina [46]3 years ago
5 0

Answer:

So the conclusion is that in presence of air net force acting downward reduces for feather and hence falls slower than coin. But in absence of air resistance, net downward force is just equal to force due to gravity which is same for both coin and feather and hence they fall down at the same rate.

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An object is placed at 1.5 m from a convex lens with a focal length of 1.0 m.
AleksAgata [21]
A. Use the thin lens equation to determine the image distance from the lens. Is the correct answer because I have no idea why
8 0
3 years ago
If the elevation in reservoir b is 100m, what must the elevation in reservoir a be if thevolume flow rate through the cast-iron
Zinaida [17]

The elevation in reservoir  at  the rate of flow using is 03m/s  is 114m.

The Reynolds range is the ratio of inertial forces to viscous forces. The Reynolds variety is a dimensionless variety used to categorize the fluids structures in which the impact of viscosity is crucial in controlling the velocities or the flow sample of a fluid.

The reason of the Reynolds number is to get a few experience of the relationship in fluid glide between inertial forces (this is those that maintain going by using Newton's first law – an item in motion stays in movement) and viscous forces, this is people who cause the fluid to come back to a forestall because of the viscosity of the fluid.

calculation,

Let L = 100 m pipe

     L1 = 150 m pipe

H f = friction losses

Using Reynolds number, relative  roughness, friction co- effiicients and friction losses

Substitute the value in equation

Z = 110= 0.48= 3.54

Z = 114m

Therefore water surface elevation at reservoir  is 114 meter.

Learn more about rate of flow here:-brainly.com/question/21630019

#SPJ4

6 0
2 years ago
Give an example of something you could do to reduce friction.
Archy [21]
Put oil on a table, that would reduce friction
5 0
3 years ago
Read 2 more answers
Certain neutron stars (extremely dense stars) are believed to be rotating at about 500 rev/s. If such a star has a radius of 17
Alexus [3.1K]

Answer:

7.22 × 10²⁹ kg

Explanation:

For the material to be in place, the gravitational force on the material must equal the centripetal force on the material.

So, F = gravitational force = GMm/R² where M = mass of neutron star, m = mass of object and R = radius of neutron star = 17 km

The centripetal force F' = mRω² where R = radius of neutron star and ω  = angular speed of neutron star

So, since F = F'

GMm/R² = mRω²

GM = R³ω²

M = R³ω²/G

Since ω = 500 rev/s = 500 × 2π rad/s = 1000π rad/s = 3141.6 rad/s = 3.142 × 10³ rad/s and r = 17 km = 17 × 10³ m and G = universal gravitational constant = 6.67 × 10⁻¹¹ Nm²/kg²

Substituting the values of the variables into M, we have

M = R³ω²/G

M = (17 × 10³ m)³(3.142 × 10³ rad/s)²/6.67 × 10⁻¹¹ Nm²/kg²

M = 4913 × 10⁹ m³ × 9.872 × 10⁶ rad²/s²/6.67 × 10⁻¹¹ Nm²/kg²

M = 48,501.942 × 10¹⁵ m³rad²/s² ÷ 6.67 × 10⁻¹¹ Nm²/kg²

M = 7217.66 × 10²⁶ kg

M = 7.21766 × 10²⁹ kg

M ≅ 7.22 × 10²⁹ kg

8 0
3 years ago
Two cylindrical resistors are made of the same material and have the same resistance. The resistors, R1 and R2, have different r
Paladinen [302]

Answer:

Option d is correct.

Explanation:

We know , resistance of a body is directly proportional to its length and inversely proportional to its area.

R=\dfrac{\rho\ L}{A}=\dfrac{\rho\ L}{\pi r^2}      ( Here, \rho is constant dependent on object material )

Writing R_1 \ and\ R_2 also :

R_1=\dfrac{\rho\ L_1}{\pi r_1^2}\ , \  R_2=\dfrac{\rho\ L_2}{\pi r_2^2}      ( since they are of same material therefore, \rho is same.)

Now , if r_2=2r_1 \ and \ 4L_1=L_2.

Then R_1=R_2

Therefore, option d. is correct.

Hence, this is the required solution.

7 0
3 years ago
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