The equation for work (W) done by an electric field is:
W = qΔV
where q is the magnitude of the charge and ΔV is the potential difference. The question gives you W and q, so plug n' play to find ΔV:
10 = 2ΔV
ΔV = 5
Answer:
a) 
b) 
Explanation:
Given:
- mass of raindrops,

- charge on the raindrops,

- horizontal distance between the raindrops,

A)
<u>From the Coulomb's Law the force between the charges is given as:</u>

we have:

<em>Now force:</em>


B)
<u>Now the acceleration on the raindrops due to the electrostatic force:</u>



Answer:it experiences no force
Explanation:
a charge moving in a direction parallel to the magnetic field experience no force.since the angle e is 0,force would also be 0
Wavelength = velocity/frequency
wavelength = v/f
v= 13km/s = change this to m/s = 13000m/s
f= 14Hz
wavelength = 13000m/s÷14Hz =928.7 m
Answer:
0.015 m/s2
Explanation:
Using Newtons 2nd law.
F = ma where F = Force applied, m = mass of the object and a = acceleration acquired.
So substitute the values in SI units.
m =
kg
Therefore F = 0.003×5 = 0.015 m/s2