All categories

3 years ago

According to the cooling curve, what is the approximate freezing point of the substance?

Physics

1 answer:

Oksana_A [137]3 years ago

3 0

Answer:

I do not know which substance you are referring to, but the freezing point of water is 32°F, or 0°C.

You might be interested in

What are the two goals of the Artemis Mission?

grin007 [14]

Answer:

The Artemis program is a U.S. government-funded international human spaceflight program that has the goal of landing the first woman and the next man on the Moon, specifically at the lunar south pole region, by 2024.

Follow me please

Mark brainliest

3 0

3 years ago

A 42.0-cm diameter disk rotates with a constant angular acceleration of 2.70 rad/s2. It starts from rest at t = 0, and a line dr

Zielflug [23.3K]

Answer:

6.21 rad/s

1.3041 m/s, 0.567 m/s²

$106.4778\ ^{\circ}$

Explanation:

$\omega_f$ = Final angular velocity

$\omega_i$ = Initial angular velocity = 0

$\alpha$ = Angular acceleration = 2.3 rad/s²

$\theta$ = Angle of rotation

t = Time taken = 2.3 s

Equation of rotational motion

$\omega_f=\omega_i+\alpha t\\\Rightarrow \omega_f=0+2.7\times 2.3\\\Rightarrow \omega_f=6.21\ rad/s$

The angular speed is 6.21 rad/s

Linear velocity is given by

$v=r\omega\\\Rightarrow v=0.21\times 6.21\\\Rightarrow v=1.3041\ m/s$

Linear velocity is 1.3041 m/s

Tangential acceleration is given by

$a_t=r\alpha\\\Rightarrow a_t=0.21\times 2.7\\\Rightarrow a_t=0.567\ m/s^2$

Tangential acceleration is 0.567 m/s²

$\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\Rightarrow \theta=0\times t+\dfrac{1}{2}\times 2.7\times 2.3^2\\\Rightarrow \theta=7.1415\ rad$

In degress the angle would be

$57.3+7.1415\times \dfrac{180}{\pi}=466.47780\ ^{\circ}$

From x axis it would be

$466.47780-360=106.4778\ ^{\circ}$

The angle is $106.4778\ ^{\circ}$ from x axis

7 0

3 years ago

Since sound is a mechanical wave it needs a ...... to travel through

Leni [432]

Answer:

medium

Examples:

A medium is a thing that the sound wave would travel through, like sound waves traveling through air. A mechanical wave cannot travel without a medium, like if the wave were trying to travel through a vacuum.

6 0

3 years ago

2. A jack exerts a vertical force of 4.5 X 103

skad [1K]

Correct Question:-

A jack exerts a vertical force of 4.5 × 10³

newtons to raise a car 0.25 meter. How much

work is done by the jack?

$\\ \\$

Given :-

$\star \sf \small force = 4.5 \times {10}^{3} \: newton$

$\star \sf \small distance = 0.25 \: meter$

$\\ \\$

To find:-

$\sf \star \: work = \: ?$

$\\ \\$

Solution:-

we know :-

$\bf \dag \boxed{ \rm work = force \times distance}$

$\\ \\$

So:-

$\dashrightarrow \sf work = force \times distance$

$\\ \\$

$\dashrightarrow \sf work = (4.5 \times 1 {0}^{3} ) \times 0.5 \\$

$\\ \\$

$\dashrightarrow \sf work = (4.5 \times 1 {0}^{3} ) \times \frac{0 \cancel.5}{10} \\$

$\\ \\$

$\dashrightarrow \sf work = (4.5 \times 1 {0}^{3} ) \times \frac{5}{10} \\$

$\\ \\$

$\dashrightarrow \sf work = (4.5 \times 1 {0}^{3} ) \times \cancel \frac{5}{10} \\$

$\\ \\$

$\dashrightarrow \sf work = \dfrac{4\cancel.5}{10} \times 1 {0}^{3} \times \dfrac{1}{2} \\$

$\\ \\$

$\dashrightarrow \sf work = \dfrac{45}{10} \times 1 {0}^{3} \times \dfrac{1}{2} \\$

$\\ \\$

$\dashrightarrow \sf work = \dfrac{45}{10 {}^{0} } \times 1 {0}^{3 - 1} \times \dfrac{1}{2} \\$

$\\ \\$

$\dashrightarrow \sf work = \dfrac{45}{10 {}^{0} } \times 1 {0}^{2} \times \dfrac{1}{2} \\$

$\\ \\$

$\dashrightarrow \sf work = \dfrac{45}{1} \times 1 {0}^{2} \times \dfrac{1}{2} \\$

$\\ \\$

$\dashrightarrow \sf work = \dfrac{45 \times 10 \times \cancel{10}}{ \cancel2} \\$

$\\ \\$

$\dashrightarrow \sf work = \dfrac{45 \times 10 \times 5}{ 1} \\$

$\\ \\$

$\dashrightarrow \sf work =225 \times 10$

$\\ \\$

$\dashrightarrow \bf work =\red{2250\: joule}$

5 0

3 years ago

A hydraulic machine has a small piston and a larger piston. Explain how a hydraulic machine multiplies force? What happens to th

Tanya [424]

Answer:

Explanation:

Pressure is equal to the force divided by the area on which it acts. Since the smaller piston has less area so from less force also we can get more efficiency in work. And according to the Pascal's principle, in a hydraulic system, pressure exerted on a piston produces an equal increase in pressure on another piston in the system. Thus by applying little force in the smaller piston, we can get same force from larger piston too. A hydraulic machine magnifies force.

6 0

3 years ago