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Ede4ka [16]
3 years ago
9

Which of the follow represent a chemical changes

Physics
1 answer:
mixer [17]3 years ago
5 0

Answer:

C) steel turning to rust in salt air

Explanation:

The missing options are:

A) ice melting to form liquid water

B) water boiling to form steam

C) steel turning to rust in salt air

D) sugar dissolving into hot coffee

In a chemical change the atoms of the reacting compounds are reordered forming new compounds. In a chemical change, new compounds appear, but in a physical change not.

Then, change of states like ice melting and water boiling are not chemical changes.

During steel rust, components of steel, like iron, are oxidized, that is, reacts with oxygen forming oxides.

The dissolution of sugar into hot coffee is a physical change in which sugar molecules get further apart in the coffee,  but they don't change.

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An object has a mass of 10 kilograms and is accelerating at 5 m/s/s, what force pushed the object?
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Answer:

hope helps

Explanation:

In a weightless environment a force of 5 Newtons is applied horizontally to the right on a rock with a mass of 1 kg and to a pebble with a mass of 0.1 kg.

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3 years ago
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What is the most important force in astronomy?
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This is probably gravity because without gravity, everything would just be some hot dust floating through space
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A 2.6 kg rock is dropped from a height of 10 m. With what speed will it strike the ground. Ignore air resistance. Solve using co
timurjin [86]

Answer:

mgh =  \frac{1}{2} m {v}^{2}  \\ v =  \sqrt{2gh}  \\  =  \sqrt{2 \times 9.8 \times 10}  \: m. {s}^{ - 1}

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3 years ago
In the problem 10 − 4 = 6, what's the correct term for the number 4?
romanna [79]

10 is the number that is subtracted from it is the MINUEND

4 is the number being subtracted its then the SUBTRAHEND

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so the correct term for 4 is SUBTRAHEND


3 0
3 years ago
You are the science officer on a visit to a distant solar system. Prior to landing on a planet you measure its diameter to be 1.
Alja [10]

Answer:

Part a)

M = 7.25 \times 10^{25} kg

Part b)

M = 2\times 10^{30} kg

Explanation:

Part a)

As we know that the diameter of the planet is given as

d = 1.8 \times 10^7 m

now the radius of the planet is given as

r = 9 \times 10^6 m

now we know that the acceleration due to gravity of the planet is given by the equation

g = \frac{GM}{r^2}

here we know that

g = 59.7 m/s^2

now from above equation we have

59.7 = \frac{(6.67 \times 10^{-11})M}{(9\times 10^6)^2}

now we have

M = 7.25 \times 10^{25} kg

Part b)

Now by kepler's law we know that

time period of revolution of planet about the star is given as

T = 2\pi \sqrt{\frac{r^3}{GM}}

so we have

\frac{T_1^2}{T_2^2} = \frac{r_1^3}{r_2^3}

now we have

\frac{1^2}{402^2} = \frac{(1.5 \times 10^11)^3}{r^3}}

rr = 8.17 \times 10^{12} m

mula of time period

402\times (365\times 24 \times 3600) = 2\pi \sqrt{\frac{(8.17\times 10^12)^3}{(6.67\times 10^{-11})M}}

Now we have

M = 2\times 10^{30} kg

7 0
3 years ago
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