Answer:
From the data we know that runner A and runner B are 11 km apart from the start because (6+5) km
So the runner from the east direction has distance as unknown km, rate= 9 k/h ; time= d/r=x/9 hr
So runner towards the west will be
distance = 11-x, rate= 8 k/h, time = d/r = (11-x)/8
So equating east and west time we have
x/9= (11-x)/8
8x=99-9x
17x=99
x=5.92 km
That is the distance covered by runner towards the east and he will meet the runner toward the west at
6-5.92=0.08 km west of the flagpole.
After 20 s, the motorcycle attains a speed of

and it continues at this speed for the next 40 s. So at 45 s, its speed is 80 m/s.
Answer:
5.77×10¹⁰ m
Explanation:
From the question,
Applying
Kepler's third law
P² = d³...................... Equation 1
Where P = Planet's period, d = distance between the center of the planet and the sun.
make d the subject of the formula n equation 1
d =
.................. Equation 2
Given: P = 0.24 sidereal.
Substitute the value of P into equation 2
d =
d = 0.386 Au
d = 0.386×1.496×10¹¹
d = 5.77×10¹⁰ m