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Ivahew [28]
3 years ago
5

A total charge Q is distributed uniformly over a large flat insulating surface of area A . If the electric field magnitude is eq

ual to 1000 NC/ at a point located a perpendicular distance of 0.1 m away from the center of the sheet, then the electric field at a point a perpendicular distance 0.2 m from the center of the sheet is:_______
a. 1000N/C
b. 500N/C
c. Impossible to say since we are not given Q and A
d. 250 N/C
Physics
1 answer:
Andrew [12]3 years ago
3 0

Answer:

a. 1000N/C

Explanation:

Data mentioned in the question

Electrical field magnitude = 1000 NC

Perpendicular distance = 0.1 m

Perpendicular distance = 0.2 m

Based on the above information, the electric field is

As we know that

E = \frac{\sigma}{2\times E_o}

where,

\sigma = surface charge density

E = distance from nearby point to sheet i.e be independent

The distance at 0.1 and 0.2, the electric field would remain the same

So,

Based on the above explanation, the first option is correct

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While traveling along a highway a driver slows from 24 m/s to 15 m/s in 12 seconds. What is the automobile's acceleration? (Reme
slava [35]

Answer:

Acceleration = -0.75 m/s²

Explanation:

Given the following data;

Initial velocity = 24 m/s

Final velocity = 15 m/s

Time = 12 seconds

To find the acceleration of the automobile;

Acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

Acceleration (a) = \frac {final \; velocity  -  initial \; velocity}{time}

Substituting into the formula, we have;

Acceleration = \frac{15 - 24}{12}

Acceleration = \frac{-9}{12}

Acceleration = -0.75 m/s²

Therefore, the automobile is decelerating because its final velocity is lesser than its initial velocity, leading to a negative value.

5 0
3 years ago
HELP ASAP PLEASE<br><br> Which of the following mechanical waves have the same energy?
serious [3.7K]

Answer:

1 and 4 is the answer

6 0
3 years ago
Read 2 more answers
stephen buys a new moped . he travels 4km south and then 6km east. how far does he need to go to get back where he started??
stiks02 [169]

Answer:

My answer is 7.2 km

Explanation:

When Stephen goes to the south and then to the east, he is drawing a right triangle, where the 4 km and 6 km sides are the cathetus of a right triangle.

Then we use the Pithagorean theorem to solve this problem. We need to find the hypotenuse.

c² = a² + b²

c² = 4² + 6²

c² = 16 + 36

c² = 52

c = 7.2 km

7 0
3 years ago
A bicyclist is in a 50-km race. She says she had an average velocity of 35.
zlopas [31]
The correct answer to this is (A. Units Only).

It shows that there is a velocity of 35, but the units are missing.
8 0
4 years ago
A ball is thrown straight up from ground level. It passes a 2-m-high window. The bottom of the window is 7.5 m off the ground. T
slamgirl [31]

Answer:

u=14.48m/s

Explanation:

From the question we are told that:

Height of window h=2m

Height of window off the ground h_g=7.5m

Time to fall and drop t=1.3s

 

Generally the Newton's equation motion  is mathematically given by

 s=ut+\frac{1}{2}at^2

Where

h=ut+\frac{1}{2}at^2

2=u1.3-\frac{1}{2}*9.8*1.3^2

2=u1.3-8.281

u=7.91m/s^2  

Generally the Newton's equation motion  is mathematically given by

2as=v^2-u^2

Where

-2gh_g=v^2-u^2

-2*9.8*7.5=(7.91)^2-u^2

-147=62.5681-u^2

u=\sqrt{209.5681}

u=14.48m/s

Therefore the  ball’s initial speed

u=14.48m/s

8 0
3 years ago
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