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Ivahew [28]
3 years ago
5

A total charge Q is distributed uniformly over a large flat insulating surface of area A . If the electric field magnitude is eq

ual to 1000 NC/ at a point located a perpendicular distance of 0.1 m away from the center of the sheet, then the electric field at a point a perpendicular distance 0.2 m from the center of the sheet is:_______
a. 1000N/C
b. 500N/C
c. Impossible to say since we are not given Q and A
d. 250 N/C
Physics
1 answer:
Andrew [12]3 years ago
3 0

Answer:

a. 1000N/C

Explanation:

Data mentioned in the question

Electrical field magnitude = 1000 NC

Perpendicular distance = 0.1 m

Perpendicular distance = 0.2 m

Based on the above information, the electric field is

As we know that

E = \frac{\sigma}{2\times E_o}

where,

\sigma = surface charge density

E = distance from nearby point to sheet i.e be independent

The distance at 0.1 and 0.2, the electric field would remain the same

So,

Based on the above explanation, the first option is correct

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8 0
1 year ago
Pls help on this one?
sattari [20]
The answer is point C
4 0
3 years ago
PLEASE ITS AN Emergency IF ITS RIGHT I WILL GIVE BRAINLIEST
Art [367]
Uh I think it’s point guard
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2 years ago
A new band sensation is playing a concert and recording it for a live album to be released this summer. The band asks the sound
Amanda [17]

The sound mixer will need to increase the amplitude of the sound wave produced by the singer which will increase the loudness of the sound.

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The amplitude of a sound wave is the maximum vertical displacement of the sound wave.

The sound mixer will need to increase the amplitude of the sound wave produced by the singer.

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8 0
2 years ago
A 2.31 kg rope is stretched between supports 10.4 m apart. If one end of the rope is tweaked, how long will it take for the resu
zlopas [31]

Answer:

t = 0.657 s

Explanation:

First, let's use the appropiate equations to solve this:

V = √T/u

This expression gives us a relation between speed of a disturbance and the properties of the material, in this case, the rope.

Where:

V: Speed of the disturbance

T: Tension of the rope

u: linear density of the rope.

The density of the rope can be calculated using the following expression:

u = M/L

Where:

M: mass of the rope

L: Length of the rope.

We already have the mass and length, which is the distance of the rope with the supports. Replacing the data we have:

u = 2.31 / 10.4 = 0.222 kg/m

Now, replacing in the first equation:

V = √55.7/0.222 = √250.9

V = 15.84 m/s

Finally the time can be calculated with the following expression:

V = L/t ----> t = L/V

Replacing:

t = 10.4 / 15.84

t = 0.657 s

4 0
3 years ago
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