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Ivahew [28]
3 years ago
5

A total charge Q is distributed uniformly over a large flat insulating surface of area A . If the electric field magnitude is eq

ual to 1000 NC/ at a point located a perpendicular distance of 0.1 m away from the center of the sheet, then the electric field at a point a perpendicular distance 0.2 m from the center of the sheet is:_______
a. 1000N/C
b. 500N/C
c. Impossible to say since we are not given Q and A
d. 250 N/C
Physics
1 answer:
Andrew [12]3 years ago
3 0

Answer:

a. 1000N/C

Explanation:

Data mentioned in the question

Electrical field magnitude = 1000 NC

Perpendicular distance = 0.1 m

Perpendicular distance = 0.2 m

Based on the above information, the electric field is

As we know that

E = \frac{\sigma}{2\times E_o}

where,

\sigma = surface charge density

E = distance from nearby point to sheet i.e be independent

The distance at 0.1 and 0.2, the electric field would remain the same

So,

Based on the above explanation, the first option is correct

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How much work must be done to stop a 1100-kg car traveling at 112 km/h?(Hint: You will need to convert the speed first.)Answer:
zimovet [89]

According to the Work-Energy Theorem, the work done on an object is equal to the change in the kinetic energy of the object:

W=\Delta K

Since the car ends with a kinetic energy of 0J (because it stops), then the work needed to stop the car is equal to the initial kinetic energy of the car:

K=\frac{1}{2}mv^2

Replace m=1100kg and v=112km/h. Write the speed in m/s. Remember that 1m/s = 3.6km/h:

\begin{gathered} K=\frac{1}{2}(1100kg)\left(112\frac{km}{h}\times\frac{1\frac{m}{s}}{3.6\frac{km}{h}}\right)^2=532,345.679...J \\  \\ \therefore K\approx532,346J \end{gathered}

Therefore, the answer is: 532,346 J.

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1 year ago
A large container is pulled 20 meters with 40 newtons of force. The power exerted is 64 watts. How long did it take to move the
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A.(20*40)/64=12.5 hope i helped
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3 years ago
When we look up at the stars, we are seeing the future", is this astronomer correct ? Why or why not ?
Andrei [34K]

Answer:

if the stars connect to a thing, then it describes.

7 0
3 years ago
1. What coefficients would balance the following equation?
Stolb23 [73]

Answer:

no question matee

Explanation:

3 0
2 years ago
Read 2 more answers
2
Xelga [282]

Answer:

About 7.67 m/s.

Explanation:

Mechanical energy is always conserved. Hence:

\displaystyle \begin{aligned} E_i & = E_f \\ \\ U_i + K_i &= U_f + K_f\end{aligned}

Where <em>U</em> is potential energy and <em>K</em> is kinetic energy.

Let the bottom of the slide be where potential energy equals zero. As a result, the final potential energy is zero. Additionally, because the child starts from rest, the initial kinetic energy is zero. Thus:

\displaystyle U_i = K_f

Substitute and solve for final velocity:
\displaystyle \begin{aligned} mgh_i &= \frac{1}{2}mv_f^2 \\ \\  2gh_i &= v^2_f \\ \\ v_f &= \sqrt{2gh_i} \\ \\ &  =\sqrt{2(9.8\text{ m/s$^2$})(3.00\text{ m})} \\ \\ & \approx 7.67\text{ m/s} \end{aligned}

In conclusion, the child's speed at the bottom of the slide is about 7.67 m/s.

8 0
2 years ago
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