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2 years ago

5

Suppose a creature from another planet has eyes that are sensitive to infrared radiation. Describe what the alien would see if i

t looked around your library. In particular, what would appear bright and what would appear dim

1 answer:

Brut [27]2 years ago

7 0

The incandescent lamp will glow quite brightly in the eyes of the creature because emits less visible light and more infrared light.

<h3>What is infrared light?</h3>

The infrared light is a part of the electromagnetic spectrum that is emitted by a hot object.

As such, the incandescent lamp will glow quite brightly in the eyes of the creature because emits less visible light and more infrared light. The florescent light which does not produce inferred rays will not be visible at all.

Learn more about infrared light:brainly.com/question/7071188

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How does the speed of light change as the index of refraction increases?.

Maksim231197 [3]

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2 years ago

How many oxygen atoms are in Ca (NO3)2

Lapatulllka [165]

There are 6 atoms of oxygen in Ca (NO3)2.

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3 years ago

How do you get: a = -ω^2*x from: a = -Aω^2*sen(ωt) ?

Firdavs [7]

Answer:

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4 years ago

A car and a train move together along straight, parallel paths with the same constant cruising speed v(initial). At t=0 the car

kogti [31]

Answer:

$t_1 = \frac{v_i}{a_i}$

$t_2 = \frac{v_i}{a_i}$

Δd = $v_it_1 = v_i^2/a_i$

Explanation:

As $v(t) = v_i + at$ , when the car is making full stop, $v(t_1) = 0$ . $a = -a_i$ . Therefore,

$0 = v_i - a_it_1\\v_i = a_it_1\\t_1 = \frac{v_i}{a_i}$

Apply the same formula above, with $v(t_2) = v_i$ and $a = a_i$ , and the car is starting from 0 speed, we have

$v_i = 0 + a_it_2\\t_2 = \frac{v_i}{a_i}$

As $s(t) = vt + \frac{at^2}{2}$ . After $t = t_1 + t_2$ , the car would have traveled a distance of

$s(t) = s(t_1) + s(t_2)\\s(t_1) = (v_it_1 - \frac{a_it_1^2}{2})\\ s(t_2) = \frac{a_it_2^2}{2}$

Hence $s(t) = (v_it_1 - \frac{a_it_1^2}{2}) + \frac{a_it_2^2}{2}$

As $t_1 = t_2$ we can simplify $s(t) = v_it_1$

After t time, the train would have traveled a distance of $s(t) = v_i(t_1 + t_2) = 2v_it_1$

Therefore, Δd would be $2v_it_1 - v_it_1 = v_it_1 = v_i^2/a_i$

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3 years ago

if a 3.1g ring is heated using 10.0 calories, its temperatures rises 17.9C calculate the specific heat capacity of the ring

Aleksandr-060686 [28]

So what you do is you use the formula shown below:

specific heat capacity = energy required / (mass * change in temperature)

here ,
energy required = 10.0°C Note that cal. is short form for °C
mass (m) = 3.1g
change in temperature (ΔT) = 17.9°C Note that "ΔT" means change in temperature

So, plugging the values into the formula, we get,

Specific heat capacity= $\frac{10}{3.1*17.9}$

= $0.1802126509$

= 0.1802 cal./g°C <span>i rounded the answer to the fourth decimal point
</span>

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4 years ago