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Ad libitum [116K]
1 year ago
9

9) 25cm³ of a liquid x of density 1.2g/cm³ is mixed with liquid of volume 30 cm³ and 0.9g/cm³ without change in volume. Calculat

e density of the mixture.​
Physics
1 answer:
tino4ka555 [31]1 year ago
8 0

Answer:

0.545g/cm OR 545kg/m(both answers are in cubic)

Explanation:

first we have to find mass of liquid x

mass= density × volume

=25 cubic centimetre × 1.2g/cm

=3g

liquid y= density × volume

=30 cubic centimetre × 0.9g/cm

= 27g

next,we add the two masses

27+3

30g(mass of the whole mixture)

formula for finding density of the mixture

Mass1+ Mass2 ÷ Volume 1+ volume 2

30g ÷55 cubic centimetre

the answer will be a recurring decimal and as we know,we write decimals in 3 significant numbers so we round off

0.5454g/cm= 0.545g/cm and in SI units it's

545kg per cubic meter

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A hiker, caught in a rainstorm might absorb 1 liter of water in her clothing. if it is windy so that this amount of water is eva
NeTakaya

Water evaporates at 100⁰C

So change in temperature = 100-20 = 80⁰C

Amount of water to be evaporated = 1 liter = 1L*1kg/liter = 1 kg

Specific heat of water is 1 calorie/gram ⁰C = 4.186 joule/gram =4186 J/kg

So heat required E = mcΔT = 1 * 4186 *80= 334880 J =334.88 kJ

So amount of heat require to evaporate water = 334.88 kJ

4 0
2 years ago
Identical forces act for the same length of time on two different masses. The change in momentum of the smaller mass is
xenn [34]

Answer:

Equal to change in momentum of larger mass.

Explanation:

We are given that

Two difference  masses .

Force act on both masses  for the same length of time.

We have to find the change in momentum of the smaller mass.

Let M and m are two masses

M>m

We know that

Change in momentum for large mass=F\Delta t

Change in momentum for small mass=F\Delta t

Because Force and length of time are same for both masses .

Hence, the change in momentum of smaller mass is equal to change in momentum of larger mass.

7 0
3 years ago
A space expedition discovers a planetary system consisting of a massive star and several spherical planets. The planets all have
Juliette [100K]

Answer:

T/√8

Explanation:

From Kepler's law, T² ∝ R³ where T = period of planet and R = radius of planet.

For planet A, period = T and radius = 2R.

For planet B, period = T' and radius = R.

So, T²/R³ = k

So, T²/(2R)³ = T'²/R³

T'² = T²R³/(2R)³

T'² = T²/8

T' = T/√8

So, the number of hours it takes Planet B to complete one revolution around the star is T/√8

7 0
2 years ago
Particles 1 and 2 of charge q1 = q2 = +3.20 × 10−19 C are on a y axis at distance d = 17.0 cm from the origin. Particle 3 of cha
mel-nik [20]

Answer:

(a) 0.17 m

(b) 5.003 m

(c) 6.38 × 10^{-26} N

(d) 7.37 ×10^{-29} N

Explanation:

(a) The minimum value of x will occur when q3 = 0 m or at origin and q1, q2 are at 0.17 m so the distance between q3 and q1, q2 is 0.17 m, therefore the <em>minimum value of x= 0.17 m</em>.

(b) The maximum value of x will occur when q3 = 5 m because it is said in the question that 5 is the maximum distance travelled by q3. To find the hypotenuse i.e. the distance between q3 and q1,q2, we use Pythagoras theorem.

h^{2} = b^{2} + p^{2}

h^{2} = 5^{2} + 0.17^{2}   \\h = \sqrt{} 25.03\\h= 5.002 m

<em>Hence, the maximum distance is 5.002 m</em>

(c) For minimum magnitude we use the minimum distance calculated in (a)

Minimum Distance = 0.17 m

For electrostatic force=     F=\frac{kq1q2}{x^{2} }

F=\frac{9 x 10^{9} x3.2x10^{-19}x 6.4x10^{-19}  }{0.17^{2} }

F= 6.38×10^{-26} N

(d) For maximum magnitude, we use the maximum distance calculated in (b)

Maximum Distance = 5.002 m

Using the formula for electrostatic force again:

F =  \frac{9x10^{9}x3.2x10^{-19}x6.4x10^{-19}   }{5.002^{2} } }

F= 7.37×10^{-29 N

4 0
2 years ago
A hovering mosquito is hit by a raindrop that is 50 times as massive and falling at 8.4 m/s, a typical raindrop speed. How fast
kenny6666 [7]

The final velocity after the collision is 8.2 m/s

Explanation:

We can solve this problem by using the law of conservation of momentum: in fact, if we consider the system to be isolated (=no external unbalanced forces), the total momentum of the raindrop+mosquito must be conserved before and after the collision.

If the collision is perfectly inelastic, moreover, the raindrop and the mosquito stick together and travel at the same velocity v after the collision.

Mathematically:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v  

where:  

m_1 is the mass of the first mosquito

u_1 = 0 is the initial velocity of the mosquito

m_2 = 50 m_1 is the mass of the raindrop

u_2 = 8.4 m/s is the initial velocity of the raindrop

v is the final combined velocity of the raindrop+mosquito

Re-arranging the equation and substituting, we find:  

m_1 u_1 + 50 m_1 u_2 = (m_1 + 50 m_1) v\\50 m_1 u_2 = 51 m_1 v\\50 u_2 = 51 v\\v=\frac{50}{51}u_2 = \frac{50}{51}(8.4)=8.2 m/s

Learn more about momentum here:

brainly.com/question/7973509  

brainly.com/question/6573742  

brainly.com/question/2370982  

brainly.com/question/9484203  

#LearnwithBrainly

4 0
3 years ago
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