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3 years ago

11

A Cessna 172 aircraft must reach a speed of 35 m/s for takeoff. How long of a runway is needed if the acceleration of the aircra

ft is a constant 3 m/s2

1 answer:

vodomira [7]3 years ago

7 0

this should be the answer to your question

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_____ is a device

erastovalidia [21]

Answer:

transformers

Explanation:

A transformer is a device that increases or decreases voltage.

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1 year ago

Where do mosquito lay eggs

MakcuM [25]

Their called rafts they lay them by surface of stagnant water

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3 years ago

Read 2 more answers

A physics student swings a tennis ball connected to a rope in a vertical circle with a constant speed of 6.29 m/s. The ball has

Alex777 [14]

Answer:

r = 0.5 m

Explanation:

First we find the angular speed of the ball by using its period:

ω = θ/t

For the time period:

ω = angular speed = ?

θ = angular displacement = 2π rad

t = time period = 0.5 s

Therefore,

ω = 2π rad/0.5 s

ω = 12.56 rad/s

Now, for the radius:

v = rω

r = v/ω

where,

v = linear speed = 6.29 m/s

r = radius = ?

r = (6.29 m/s)/(12.56 rad/s)

<u>r = 0.5 m</u>

8 0

3 years ago

Which of the following IS NOT a part of an electromagnet?

Agata [3.3K]

I'd go with electricity source. Good luck!!

3 0

3 years ago

Starting at 1.0 m/s, a cheetah runs with a constant acceleration for 4.8 s reaching a speed of 28 m/s. What is the acceleration

LenaWriter [7]

Answer:

c. $5.6m/s^2$

Explanation:

Initial velocity of cheetah,u=1 m/s

Time taken by cheetah =4.8 s

Final velocity of cheetah,v=28 m/s

We have to find the acceleration of this cheetah.

We know that

Acceleration, $a=\frac{v-u}{t}$

Where v=Final velocity of object

u=Initial velocity of object

t=Time taken by object

Using the formula

Then, we get

Acceleration, a= $\frac{28-1}{4.8}=\frac{27}{4.8} m/s^2$

Acceleration= $a=5.6 m/s^2$

Hence, the acceleration of cheetah= $5.6m/s^2$

5 0

3 years ago