The change in speed of this object is 3m/s
According to Newton's second law;
F = ma
F = mv/t
Given the following parameters
Force F = 8.0N
mass m = 16kg
time t = 4.0s
Required
speed v
Substitute the given parameters into the formula
v = Ft/m
v = 8 * 6/16
v = 48/16
v = 3m/s
Hence the change in speed of this object is 3m/s
Learn more here: brainly.com/question/19072061
The answer should be B. a stable isotope to a decaying isotope.
It's not possible to answer the question exactly the way it's written.
That's because we don't know anything about the direction they
drive at any time during the trip.
You see, "velocity" is not just a word that you use for 'speed' when
you want to sound smart and technical, like this question is doing.
"Velocity" is a quantity that's made up of speed AND THE DIRECTION
of the motion. If you don't know the direction of the motion, then you
CAN'T tell the velocity, only the speed.
Here are the average speeds that Lori's family drove on each leg
of their trip:
Speed = (distance covered) / (time to cover the distance) .
Leg-A:
Speed = 15km/10min = 1.5 km/min
Leg-B:
Speed = 20km/15min = (1 and 1/3) km/min
Leg-C
Speed = 24km/12min = 2 km/min
Leg-D:
Speed = 36km/9min = 4 km/min
Leg-E:
Speed = 14km/14min = 1 km/min
From lowest speed to highest speed, they line up like this:
[Leg-E] ==> [Leg-B] ==> [Leg-A] ==> [Leg-C] ==> [Leg-D]
1.0 . . . . . . . . 1.3 . . . . . . . 1.5 . . . . . . . 2.0 . . . . . . . 4.0 . . . . km/minute
Whoever drove Leg-D should have been roundly chastised
and then abandoned by the rest of the family. 36 km in 9 minutes
(4 km per minute) is just about 149 miles per hour !
If the mass of both of the objects is doubled, then the force of gravity between them is quadrupled; and so on. Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces
