All categories

1 year ago

What is the kinetic energy of a 12 kg ball moving at a speed of 15 m/s?

Physics

1 answer:

vivado [14]1 year ago

3 0

Answer:

1350 N

Explanation:

KE = ½mv²

KE = ½(12)(15²)

KE = 1350 N

You might be interested in

HELPPPPP !!!!

Nataly [62]

Your answer is C)

a)t=2.78 sec

b)R=835.03 m

Explanation:

Given that

h= 38 m

u=300 m/s

here given that

The finally y=0

t=2.78 sec

The horizontal distance,R

R= u x t

R=300 x 2.78

R=835.03 m

The vertical component of velocity before the strike

4 0

2 years ago

A 225 kg block is pulled by two horizontal forces. The first force is 178 N at a 41.7-degree angle and the second is 259 N at a

yawa3891 [41]

Answer:

52.9 N, 364.7 N

Explanation:

First of all, we need to resolve both forces along the x- and y- direction. We have:

- Force A (178 N)

$A_x = (178 N)(cos 41.7^{\circ})=132.9 N\\A_y = (178 N)(sin 41.7^{\circ})=118.4 N$

- Force B (259 N)

$B_x = (259 N)(cos 108^{\circ})=-80.0 N\\B_y = (259 N)(sin 108^{\circ})=246.3 N$

So the x- and y- component of the total force acting on the block are:

$R_x = A_x + B_x = 132.9 N - 80.0 N =52.9 N\\R_y = A_y + B_y = 118.4 N +246.3 N = 364.7 N$

7 0

3 years ago

the hot gas lines need to be insulated? A never B always C if they are exposed to cold temperatures that could cause the refrige

muminat

The answer is a because it never needs to be insulated

8 0

2 years ago

Two important economic activities in Norden are _____.

tensa zangetsu [6.8K]

Fishing and Agriculture.

7 0

3 years ago

Read 2 more answers

You weigh 730N. What would you weigh if the earth were six times as massive as it is and its radius were four times its present

Ber [7]

The new weight is 273.8 N

Explanation:

The weight of an object on Earth is given by

$W=mg$

where

m is the mass of the object

g is the acceleration of gravity

The acceleration of gravity at the Earth's surface can be rewritten as

$g=\frac{GM}{R^2}$

where

G is the gravitational constant

M is the Earth's mass

R is the Earth's radius

Substituting into the previous equation,

$W=\frac{GMm}{R^2}$

We said that in normal conditions, the weight of the person is 730 N:

$W=\frac{GMm}{R^2}=730 N$

Later, we are said that:

The mass of the Earth increases by a factor of 6, $M'=6M$
The radius of the Earth increases by a factor of 4, $R'=4R$

Substituting into the equation, we find the new weight of the person in these conditions:

$W'=\frac{G(6M)m}{(4R)^2}=\frac{6}{16}(\frac{GMm}{R^2})=\frac{3}{8}W$

So, the new weight is 3/8 of the original weight, therefore:

$W'=\frac{3}{8}(730)=273.8 N$

Learn more about gravity:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

3 0

2 years ago