1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
frozen [14]
2 years ago
11

Two boxes on opposite ends of a massless board that is 3.0 m long. The board is supported in the middle by a fulcrum. The box on

the left has a mass (m1) of 25 kg, and the box on the right has a mass (m2) of 15kg. How far should the fulcrum be positioned from the left side of the board in order to balance the masses horizontally?
a. 0.38 m
b. 1.1 m
c. 0.60 m
d. 1.9 m
Physics
1 answer:
rosijanka [135]2 years ago
4 0

Answer:

b. 1.1 m

Explanation:

It is given that the total distance between the masses is equal to the length of the board, which is 3 m. Therefore,

s_{1} + s_{2} = 3\ m\\\\s_{2} = 3\ m - s_{1}\ --------- eqn(1)

where,

s₁ = distance of fulcrum from left mass

s₂ = distance of fulcrum from right mass

In order to achieve balance, the torque due to both masses must be equal:

T_{1} = T_{2}\\m_{1}s_{1} = m_{2}s_{2}\\(25\ kg)(s_{1}) = (15\ kg)(s_{2})\\\\\frac{15\ kg}{25\ kg}(s_{2}) = s_{1}\\\\using\ eqn(1):\\(0.6)(3\ m - s_{1}) = s_{1}\\1.8\ m = 1.6\ s_{1}\\s_{1} = \frac{1.8\ m}{1.6}

s₁ = 1.1 m

Hence, the correct option is:

<u>b. 1.1 m</u>

You might be interested in
In a certain time period a coil of wire is rotated from one orientation to another with respect to a uniform 0.38-T magnetic fie
juin [17]
<h2>The emf produced is 7.2 V</h2>

Explanation:

When coil is placed in the magnetic field , the flux attached with it can be found by the relation . Flux Ф = the dot product of magnetic field and area of coil .

Thus Ф = B A cosθ

here B is magnetic field strength and A is the area of coil .

The angle θ is the angle between coil and field direction .

When coil rotates , the angle varies . By which the flux varies . The emf is produced in coil due to variation of flux . The relation for this is

The emf produced ξ = - \frac{d\phi}{dt} =  B A sinθ \frac{d\theta}{dt}

Now in the given problem

5 = 0.38 x A x \frac{d\theta}{dt}                            I

Now if the magnetic field is 0.55 T and all the other terms are same , the emf produced

ξ = 0.55 x A x \frac{d\theta}{dt}                              Ii

dividing II by I , we have

\frac{\xi}{5} = \frac{0.55}{0.38} = 1.45

or ξ = 7.2 V

6 0
3 years ago
Can someone give me 5 differences for each velocity and speed.<br> FOR EACH...
VARVARA [1.3K]

Answer:

132-123+ere

Explanation:

sdsdsd

5 0
3 years ago
Read 2 more answers
Astronaut John Glenn was the first American to _____.
Alona [7]
He was the first American to orbit the earth.
3 0
3 years ago
Read 2 more answers
If it requires 4.5 J of work to stretch a particular spring by 2.3 cm from its equilibrium length, how much more work will be re
saveliy_v [14]

Answer:

\Delta W=24.1162\ J

Explanation:

Given:

  • work done to stretch the spring, W=4.5\ J
  • length through which the spring is stretched beyond equilibrium, \Delta x=2.3\ cm=0.023\ m
  • additional stretch in the spring length, \delta x=3.5\ cm=0.035\ m

<u>We know the work done in stretching the spring is given as:</u>

W=\frac{1}{2} \times k.\Delta x^2

where:

k = stiffness constant

4.5=0.5\times k\times 0.023^2

k=17013.2325\ N.m^{-1}

Now the work done in stretching the spring from equilibrium to (\Delta x+\delta x):

W'=0.5\times k.(\Delta x+\delta x)^2

W'=0.5\times 17013.2325\times 0.058^2

W'=28.6162\ J

So, the amount of extra work done:

\Delta W=W'-W

\Delta W=28.6162-4.5

\Delta W=24.1162\ J

4 0
2 years ago
A raindrop falls to the ground from a raincloud at an altitude of 3000 meters.
Dmitrij [34]

Answer:

24.7 s

Explanation:

Question is appear to be missing. Found it on google:

"a) If there were no air resistance, how long would it take to fall?"

Solution:

We can solve the problem by using the following equation of motion for a uniform accelerated motion:

d=ut+\frac{1}{2}at^2

where

d = -3000 m is the displacement of the raindrop (negative because in the downward direction)

u = 0 is the initial velocity of the raindrop if we assume it starts from rest

t is the time taken for the fall

a = g = -9.8 m/s^2 is the acceleration of gravity

Solving the equation for t, we find:

t=\sqrt{\frac{2d}{g}}=\sqrt{\frac{2(-3000)}{-9.8}}=24.7 s

3 0
3 years ago
Read 2 more answers
Other questions:
  • Calculate the gravitational potential energy of a 1200 kg car at the top of a hill that is 42 m high.
    14·1 answer
  • Vector A with arrow, which is directed along an x axis, is to be added to vector B with arrow, which has a magnitude of 5.5 m. T
    8·1 answer
  • Please help with 9 &amp; 10
    11·1 answer
  • At what minimum speed must a roller coaster be traveling when upside down at the top of a circle so that the passengers do not f
    6·1 answer
  • Olivia is on a swing at the playground at which point is her kinetic energy increasing and her potential energy decreasing
    8·2 answers
  • Direct current made it possible to distribute electric power over greater areas.
    10·1 answer
  • A 6.00 cm tall light bulb is placed a distance of 54.2 cm from a double convex lens
    14·1 answer
  • Which diagram represents an open circuit?
    5·2 answers
  • A diver 50 m deep in 10∘C fresh water exhales a 1.0-cm-diameter bubble. What is the bubble's diameter just as it reaches the sur
    7·1 answer
  • Which of the following is NOT a characteristic of noble gases?
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!