All categories

3 years ago

How is voltmeter connected in the circuit to measure the potential difference between two points?

Physics

1 answer:

34kurt3 years ago

7 0

Voltmeter is used to find the potential difference between two points.

We always connect it in parallel to the points where we need the potential difference.

Here in order to make the reading accurate we can increase the resistance of voltmeter so that it can not withdraw any current from the circuit.

You might be interested in

If you shine a light of frequency 375hz on a double slit setup , and you measure the slit separation to be 950 nm and the screen

amm1812

Answer:

y = 33.93 10⁵ m

Explanation:

This is an interference exercise, for the contributory interference is described by the expression

d sin θ = m λ

let's use trigonometry for the angle

tan θ = y / L

how the angles are small

tan θ = sin θ / cos tea = sin θ

we substitute

sin θ = y / L

d y / L = m λ

y = m λ L / d

the light fulfills the relation of the waves

c = λ f

λ = c / f

λ = 3 10⁸ /375

λ = 8 10⁵ m

first order m = 1

let's calculate

y = 1 8 10⁵ 4030 10-9 / 950 10-9

y = 33.93 10⁵ m

6 0

2 years ago

Help me on this question

nikitadnepr [17]

Adjust the height of the wooden rod so that it just touches the surface of the water. Switch on the lamp and motor and adjust the speed of the motor until low frequency waves can be clearly observed... Count the number of waves passing a point in ten seconds then Divide by ten to record frequency.

6 0

2 years ago

The quartz crystal used in an electric watch vibrates with a frequency of 32,768 Hz. What is the period of the crystal's motion?

Elan Coil [88]

Answer:

Time period, $T=3.05\times 10^{-5}\ s$

Explanation:

Given that,

The quartz crystal used in an electric watch vibrates with a frequency of 32,768 Hz, f = 32768 Hz

We need to find the period of the crystal's motion. The relationship between the frequency and the time period is given by :

$T=\dfrac{1}{f}$

T is the time period of the crystal's motion.

Time period is given by :

$T=\dfrac{1}{32768}$

$T=3.05\times 10^{-5}\ s$

So, the time period of the crystal's motion is $3.05\times 10^{-5}\ s$ . Hence, this is the required solution.

8 0

2 years ago

6^5/2^3= what is the answer please

kogti [31]

Answer:

972

Explanation:

6^5/2^3

=7776/8

=972

6 0

2 years ago

Read 2 more answers

What are (a) the charge and (b) the charge density on the surface of a conducting sphere of radius 0.20 m whose potential is 240

Lady bird [3.3K]

Answer:

(a) charge q=5.33 nC

(b) charge density σ=10.62 nC/m²

Explanation:

Given data

radius r=0.20 m

potential V=240 V

coulombs constant k=9×10⁹Nm²/C²

To find

(a) charge q

(b) charge density σ

Solution

For (a) charge q

$V_{potential}=kq/r\\ q=rV_{potential}/k\\q=\frac{(0.20)(240)}{9*10^{9} }\\ q=5.333*10^{-9}C\\or\\ q=5.33nC$

For (b) charge density

As charge density σ is given as:

σ=q/(4πR²)

σ=(5.333×10⁻⁹) / (4π×(0.20)²)

σ=10.62 nC/m²

3 0

2 years ago