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4 years ago

7

How is voltmeter connected in the circuit to measure the potential difference between two points?

1 answer:

34kurt4 years ago

7 0

Voltmeter is used to find the potential difference between two points.

We always connect it in parallel to the points where we need the potential difference.

Here in order to make the reading accurate we can increase the resistance of voltmeter so that it can not withdraw any current from the circuit.

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What will Al’s charge be when it comes an ion

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The charge will be 3+

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4 years ago

A light source radiates 60.0 W of single-wavelength sinusoidal light uniformly in all directions. What is the average intensity

umka21 [38]

Answer: $29.85\ W/m^2$

Explanation:

Given

Power $P=60\ W$

Distance from the light source $r=0.4\ m$

Intensity is given by

$I=\dfrac{P}{4\pi r^2}$

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3 years ago

Read 2 more answers

A shell is fired from the ground with an initial speed of 1.74 ✕ 103 m/s at an initial angle of 58° to the horizontal.

ValentinkaMS [17]

Answer:

a) horizontal range s=277671.77 m

b) time the shell is in motion 301.143 s

Explanation:

Is a parabolic movement so the velocity have two components:

$v = 1.74 x 10^{3} ( \frac{m}{s} )$

$\alpha = 58$ °

$v_{y} =v*Sen (\alpha )\\v_{x} =v*Cos (\alpha )$

$v_{y} =1740*Sen (58 )\\v_{x} =1740*Cos (58)$

$v_{y} = 1475.603 \frac{m}{s}\\v_{x} = 922.059 \frac{m}{s}\\$

$t= \frac{2*v_{y} }{g}$

$t= \frac{2*1475.603 }{9.8}$

$t= 301.143 s$

$v= \frac{s}{t} \\s= v_{x}*t$

$s= 922.059 \frac{m}{s} * 301.143 s$

$s = 277671.77 m$

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4 years ago

You are in your car driving on a highway at 23 m/s when you glance in the passenger-side mirror (a convex mirror with radius of

Irina-Kira [14]

Answer:

v = 26. 88 m/s +23 m/s

Explanation:

u = 23 m/s, r = 150 cm, u₁ = 2.0 m/s, s =2.0 m

$\frac{1}{s} +\frac{1}{s'} = \frac{2}{R}$

$\frac{1}{2.0 m} +\frac{1}{s'} = \frac{2}{1.50 m}$

Solve s'

$\frac{1}{s'} = \frac{2}{1.50 m} - \frac{1}{2.0 m}$

$\frac{1}{s'} = 1.833 m$

$s' = - 0.545 m$

To determine the speed of the trick to the highway

$\frac{ds}{dt}= \frac{s^2* \frac{ds}{dt}}{s' ^2} =\frac{2.0 ^2m * 2.0 m/s}{0.545^2m}$

$\frac{ds}{dt} = 26.88 m/s$

Now to determine the velocity highway is going to be

v = ds/dt + u

v = 26. 88 m/s +23 m/s

8 0

3 years ago

Round your decimal answer to the nearest hundredth.

trasher [3.6K]

Son of c is .72

Have a good night

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3 years ago