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Ainat [17]
3 years ago
10

Mmmm hmmmm Crlly yup pop I’m I u jouk is the season go ju

Physics
2 answers:
Gala2k [10]3 years ago
5 0

Answer:

no

Explanation:

valkas [14]3 years ago
3 0

Answer:

:OOO

Explanation:

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How many electrons have been removed from a positively charged electroscope if it has a net charge of 6x10-11?
faltersainse [42]

Answer:

<h3>Because one Coulomb of charge is an abnormally large quantity of charge, the units of microCoulombs (µC) or nanoCoulombs (nC) are more commonly used as the unit of measurement of charge. To illustrate the magnitude of 1 Coulomb, an object would need an excess of 6.25 x 1018 electrons to have a total charge of -1 C.</h3>

Explanation:

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4 0
3 years ago
What is most likely the amount of energy available at a trophic level of primary consumers if the amount of energy available to
docker41 [41]

Answer:

200 kilocalories

Explanation:

6 0
2 years ago
Which resistors in the circuit are connected in series?
Lisa [10]

Answer:

it's C and D... do you understand?

7 0
2 years ago
a scale model of the solar system where 50 cm represents 1.0x10 to the fifth km is actual distance what would be the dimension o
Fofino [41]

The distance between Mars and the Sun in the scale model would be 1140 m

Explanation:

In this scale model, we have:

x_1 = 50 cm represents an actual distance of

d_1 = 1.0\cdot 10^5 km

The actual distance between Mars and the Sun is 228 million km, therefore

d_2=228\cdot 10^6 km

On the scale model, this would corresponds to a distance of x_2.

Therefore, we can write the following proportion:

\frac{x_1}{d_1}=\frac{x_2}{d_2}

And solving for x_2, we find:

x_2=\frac{x_1 d_2}{d_1}=\frac{(50)(228\cdot 10^6)}{1\cdot 10^5}=1.14\cdot 10^5 cm = 1140 m

Learn more about distance:

brainly.com/question/3969582

#LearnwithBrainly

4 0
3 years ago
Can someone please help me with science.
alekssr [168]

Answer:

The answers to your questions are given below

Explanation:

22. The energy of an electromagnetic wave and it's frequency are related by the following equation:

E = hf

Where:

E => is the energy

h => is the Planck's constant

f => is the frequency

From the equation i.e E = hf, we can conclude that the energy of a wave is directly proportional to it's frequency. This implies that an increase in the frequency of the wave will lead to an increase in the energy of the wave and also, a decrease in the frequency will lead to a decrease in the energy of the wave.

23. Gamma ray and radio wave are both electromagnetic waves. All electromagnetic waves has a constant speed of 3×10⁸ m/s in space.

Thus, gamma ray and radio wave have the same speed in space.

3 0
3 years ago
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