Question: A commuter backs her car out of her garage with an acceleration of 1.4 m/s² (a) How long does it take her to reach a speed of 2.00 m/s
Answer:
1.43 s
Explanation:
Applying,
a = (v-u)/t........... Equation 1
Where a = acceleration, v = final velocity, u = initial velocity, t = time
make t the subject of the equation
t = (v-u)/a........... Equation 2
From the question,
Given: v = 2 m/s, u = 0m/s (from rest), a = 1.4 m/s²
Substitute into equation 2
t = (2-0)/1.4
t = 1.43 s
By chromatography it's the answer
Answer:
14.7 m/sec.
Explanation:
We will go about using the mathematical formula,
Vf - Vo = gT.
To break it down,
Vf = Velocity of the apple just before hitting the ground.
Vo = Initial velocity of apple = 0
T = Time for apple to hit the ground = 1.5 sec
g = Acceleration due to gravity = 9.8 m/sec^2
We then need to substitute appropriate values,
<em>Vf - 0 = 9.8(1.5) </em>
<em />
<em>Vf = 14.7 m/sec. </em>
<em />
It could be, depending on WHAT distance was graphed,
and how the student labeled the graph's axes.
Most likely, however, she probably drew the graph ...
-- with time on the x-axis increasing to the right,
-- with distance on the y-axis increasing upward,
-- to show the distance FROM the starting point
NOT the distance remaining to the destination.
If that's how she set it up, or if any two of these items are
the other way around, then the line could not slope downward.
THAT would say that the distance from the starting point is
decreasing as time goes on, or the distance remaining to the
destination is increasing as time goes on. That would be silly.
Answer:
lol you literally answered a question with a link and you're telling people not to?