Acceleration due to gravity at the surface of Mars is given by the formula
here
M = mass of Mars
R = radius of Mars
Now if we take a point which is at height 3 times the radius of Mars from its surface
So the acceleration due to gravity is given as
now using this
so here the gravity is 16 times lesser than gravity at surface
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Answer:
The velocity of block B when the energy stored in the spring bumpers is max = 2.5m/s
Explanation:
An head on collision is aka elastic collision and in elastic collision momentum and energy is conserved that is the total momentum before collision = total momentum after collision
Given
Mass of block A mA = 3kg, initial Velocity of block A vA1 = 5m/s, Final velocity = vA2
Mass of block B mB = 9kg, Initial velocity of block B vB1 = 0m/s, Final velocity = vB2
Therefore we have the equation
1)mAvA1 + mBvB1 = mAvA2 + mBvB2
Also in elastic collision between 2 objects, the relative velocities before and after the collision have the same magnitude but opposite direction
vA1 - vB1 = vB2 - vA2
vA2 = vB2 - vA1 when vB1 = 0
Substitute into the equation we have
(3*5)+(9*0) = 3*(vB2-vA1) + (9*vB2)
15 = 3vB2 - 3vA1 +9vB2
15=3vB2 - (3*5) + 9vB2
15+15 = 12vB2
vB2 = 2.5m/s
10.7 or round it up to 11
Electronegativity, symbol χ, measures the tendency of an atom to attract a shared pair of electrons (or electron density). An atom's electronegativity is affected by both its atomic number and the distance at which its valence electrons reside from the charged nucleus.