<h2>Acceleration due to gravity in moon is 1.5 m/s²</h2>
Explanation:
We have equation of motion s = ut + 0.5 at²
Here the ball travels 3 m less distance in fifth second compared to third second.
That is
s₃ = s₅ + 3
Now we have
Distance traveled in third second, s₃ = u x 3 - 0.5 x g x 3² - u x 2 - 0.5 x g x 2²
s₃ = u - 2.5 g
Also
Distance traveled in fifth second, s₅ = u x 5 - 0.5 x g x 5² - u x 4 - 0.5 x g x 4²
s₅ = u - 4.5 g
That is
u - 2.5 g = u - 4.5 g + 3
2 g = 3
g = 1.5 m/s²
Acceleration due to gravity in moon = 1.5 m/s²
Answer:
a)η = 0.088
b) η = 0.5
Explanation:
a) The attached figure shows the P-V diagram for the process described in the exercise. According to that figure, the work during process 1-2 is equal to:
W(1-2) = -n*R*T1*ln(vi/vf) = -n*R*T1*ln(V/(V/2)) = -n*R*T1*ln(2)
the work during process 2-3 is equal to:
W(2-3) = nR*(T2-T1)
The work done during the 3-1 process equals zero, because the volume is constant. The specific heat for the molar specific heat equals:
cp = 7*R/2, where R is gas constant.
Qin = n*cp*(T2-T1) = 7*n*R/2*(T2-T1)
the efficiency of the cycle is equal to:
η = (W(1-2) + W(2,3))/Qin = (-n*R*T1*ln2 + n*R*(T2-T1))/(7*n*R/2*(T2-T1) = (2/7)*(1-(ln2/((T2/T1)-1)))
if we write the expression between volume and temperature, we have:
T2/T1 = v1/v2
T2/T1 = v/(v/2))
T2/T1 = 2
η = (2/7)*(1-(ln2/(2-1))) = 0.088
b)
The equation for efficiency of Carnot will be equal to:
η = 1-(T1/T2) = 1 - (1/2) = 0.5
Using conservation of momentum, we can solve for the force that the air bag exerts on the person.
Recall the equation for momentum (p):
We can solve for total momentum, then divide by out time interval. This gets us:
F = 4800N
Answer:
The velocity at exit of the nozzle is 175.8 m/s
Solution:
As per the question:
Air density inside the rocket,
Speed, v = 1.20 m/s
The inner diameter of the rocket,
The inner radius of the rocket,
The exit diameter of the nozzle,
The exit radius of the nozzle,
Air density inside the nozzle,
Now,
To calculate the air speed when it leaves the nozzle:
Mass rate in the interior of the rocket,
Mass rate in the outlet of the nozzle,
Now,
Now,
We know that:
v' = 175.8 m/s
I ain’t never seen two pretty best friends