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Olegator [25]
1 year ago
8

**please look at attached photo for proper understanding* Inside a cathode ray tube, an electron is in the presence of a uniform

electric field with a magnitude of 295 N/C.
What is the magnitude of the acceleration of the electron (in m/s2)?

_____m/s2


The electron is initially at rest. What is its speed (in m/s) after 8.50 ✕ 10−9 s?

________m/s

Physics
1 answer:
yanalaym [24]1 year ago
5 0

The magnitude of the acceleration of the electron is 5.187 x 10¹³ m/s².

The speed of the electron at the given time is 4.41 x 10⁵ m/s.

<h3>Acceleration of the electron</h3>

The magnitude of the acceleration of the electron is calculated as follows;

Force on the electron, F = ma = Eq

ma = Eq

a = Eq/m

where;

  • E is electric field
  • q is charge of electron
  • m is mass of electron

a = (295 x 1.6 x 10⁻¹⁹) / (9.1 x 10⁻³¹)

a = 5.187 x 10¹³ m/s²

<h3>Speed of the electron</h3>

The speed of the electron at the given time is calculated as follows;

v = at

v = ( 5.187 x 10¹³)(8.5 x 10⁻⁹)

v = 4.41 x 10⁵ m/s

Thus, the magnitude of the acceleration of the electron is 5.187 x 10¹³ m/s².

The speed of the electron at the given time is 4.41 x 10⁵ m/s.

Learn more about acceleration here: brainly.com/question/605631

#SPJ1

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Lesson 11: electricity &amp; magnetism unit test physical science b unit 5: electricity and magnetism (connexus)
vovikov84 [41]

Electricity and magnetism can be considered as part of the same phenomenon because both are generated by electromagnetic forces.

<h3>What is electricity?</h3>

Electricity is the movement or flow of negatively charged electrons through a suitable conductor where a charge is applied.

Moreover, magnetism is a natural phenomenon caused by the generation/movement of electric charges.

In conclusion, electricity and magnetism can be considered as part of the same phenomenon because both are generated by electromagnetic forces.

Learn more on electricity and magnetism here:

brainly.com/question/25144822

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5 0
2 years ago
From the top of a cliff, a person uses a slingshot to fire a pebble straight downward, which is the negative direction. The init
Talja [164]

Answer:

\vec{a} = -(9.8~{\rm m/s^2})\^y

Explanation:

Regardless of the initial velocity of the pebble, the acceleration of the pebble is equal to the gravitational acceleration which is equal to 9.8 m/s2 towards downwards direction.

This can be shown by Newton's Second Law. According to the law, the net force applied on an object is equal to mass times acceleration of that object.

During the downward motion, the only force acting on the pebble is the gravitational force, hence its acceleration is equal to gravitational acceleration.

8 0
3 years ago
A hiker hikes south 0.7 km. she then hikes east 2.4 km. what is the magnitude and unit of her displacement from her initial posi
Usimov [2.4K]
If you illustrate the problem, you will somewhat come up with the figure shown. The missing value is the hypotenuse of the right triangle. Using the pythagorean theorems, the value is determined to be

x = √(0.7^2 + 2.4^2)
x = 2.5 km

2.5 km is the magnitude of the distance. If you want to incorporate the displacement, the answer is reported as 2.5 km, southeast. The direction is determined from the starting point to the endpoint.

7 0
3 years ago
Which circuit has the larger equivalent resistance: a circuit with two 10 ohm resistors connected in parallel or a circuit with
Ganezh [65]

Answer:

A circuit with two 10 ohm resistors connected in series.

Explanation:

The formula for the equivalent resistance for resistors in parallel is

\frac{1}{Rt} = \frac{1}{R1} + \frac{1}{R2}   So if R1=R2= 10  \frac{1}{Rt} = \frac{1}{10} + \frac{1}{10} = \frac{2}{10}   Rt =\frac{10}{2} =5 ohm

The formula for the equivalent resistance for resistors in series is

Rt = R1 + R2  So Rt= 10 + 10 = 20

6 0
3 years ago
The photon energies used in different types of medical x-ray imaging vary widely, depending upon the application. Single dental
Alchen [17]

1. Single dental x-rays: 5.0\cdot 10^{-11}m

The energy of the photon is

E=25 keV = 25,000 eV

Using the conversion factor

1 eV=1.6\cdot 10^{-19} J

we can convert it into Joules:

E=(25,000 eV)(1.6\cdot 10^{-19}J/eV)=4\cdot 10^{-15} J

The relationship between photon energy and wavelength is

\lambda=\frac{hc}{E}

where

h=6.63\cdot 10^{-34} Js is the Planck constant

c=3\cdot 10^8 m/s is the speed of light

E is the energy

Substituting into the formula, we find

\lambda=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{4\cdot 10^{-15} J}=5.0\cdot 10^{-11}m

2. Microtomography: 2.0\cdot 10^{-11} m

The energy of these photons is 2.5 times greater, so

E=(2.5)(4\cdot 10^{-15} J)=1\cdot 10^{-14} J

And by applying the same formula used at point 1, we find the corresponding wavelength:

\lambda=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{1\cdot 10^{-14} J}=2.0\cdot 10^{-11}m

6 0
3 years ago
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