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Yuki888 [10]
4 years ago
13

Explain how carbon is conserved in the carbon cycle.

Chemistry
1 answer:
Sonja [21]4 years ago
6 0

Most of the carbon is put away in sedimentary carbonates and kerogens, with the rest being spread between the sea, the air, biomass, for example, plants and creatures, and petroleum products

<u>Explanation</u>:

  • The carbon cycle is the procedure where carbon goes from the surrounding into living beings and to the Earth and then again goes into the air. Plants take carbon dioxide from the air and use it for food preparation. Creatures at that point eat the nourishment and carbon is put away in their bodies or discharged as CO2 through the breath.  
  • Most of the carbon is put away in sedimentary carbonates and kerogens, with the rest being spread between the sea, the air, biomass, for example, plants and creatures, and petroleum products. This is known as carbon storage.  
  • For instance, carbon, a fundamental component in natural particles, is preserved as it is moved from inorganic carbon in a biological system to natural atoms in living life forms of the biological system and back as inorganic carbon to the earth.
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Element A has an electronegativity of 2.20. Element B has an electronegativity of 3.44. The bond of molecule AB is then best des
sashaice [31]

Answer: The bond of molecule AB is then best described as a covalent bond

Explanation: The bond molecule AB is covalent because the difference in their electronegativity is not very big

4 0
3 years ago
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The average propane cylinder for a residential grill holds approximately 18 kg of propane. how much energy (in kj) is released b
Angelina_Jolie [31]
Let's begin with the basic values  that will be used in the solution.

The formula of propane is C3H8. It is an alkane, a hydrocarbon with the general formula of CnH2n+2. Notice that hydrocarbons have only Carbon and Hydrogen atoms. Its molar mass (M) is 44 g.

Molar Mass Calculation is done as like that
C=12 g/mol, H=1 g/mol. 1 mole propane has 3 moles Carbon atoms and 8 mole Hydrogen atoms. M(
C3H8)= 3*12+ 8*1= 44 g

Combustion reaction of hydrocarbons gives carbon dioxide and water by releasing energy. That energy is called as enthalpy of combustion (
ΔHc°).  

ΔHc° of propane equals -2202.0 kj/mol. Burning of 1 mole C3H8 releases 2202 kj energy. Minus sign only indicates that the energy is given out ( an exothermic reaction ).

Let's write the combustion reaction.
C3H8 + O2 ---> CO2 + H20 (unbalanced) 
ΔHc° = -2202 kj/mol

Now, we calculate mole of 20 kg propane. Convert kilogram into gram since we use molar mass is defined in grams.
mole=mass/molar mass ; n=m/M ; n= 20000 g /44 (g/mol)=454 mole

1 mole propane releases 2202 kj energy.
454 mole propane release 2202 kj *454= 1000909 kj

The answer is 1000909 kj.



6 0
4 years ago
Name three organelles and explain the function of each.
aliya0001 [1]
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Conditions inside lysosomes have been shown to be acidic. These conditions are maintained by the lysosome membrane thus providing favorable conditions.


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4 0
3 years ago
Which of the following elements exists as a diatomic molecule? Argon, Hydrogen, Boron, Sulfur
Elis [28]
Diatomic molecules are the molecules that you can find them in natural bonded to itself. example: O₂, N₂ or Br₂. 

the answer is hydrogen --->  H₂

I have attached a little trick to remember these.

5 0
4 years ago
Calculate the number of mg of Allura Red present in an 10 fluid ounce glass of the beverage you used in this lab. Assume that th
il63 [147K]

Answer : The mass of Allura Red present in an 10 fluid ounce glass of the beverage is, 7.634 mg.

Explanation : Given,

Volume of solution = 10 fl oz = 295.735 mL

Molar mass of Allura Red = 496.42 g/mole

Concentration of Allura Red (Molarity) = 0.000052 M

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

\text{Molarity}=\frac{\text{Mass of Allura Red}\times 1000}{\text{Molar mass of Allura Red}\times \text{Volume of solution (in mL)}}

Now put all the given values in this formula, we get:

0.000052M=\frac{\text{Mass of Allura Red}\times 1000}{496.42g/mole\times 295.735mL}

\text{Mass of Allura Red}=0.007634g=7.634mg

Therefore, the mass of Allura Red present in an 10 fluid ounce glass of the beverage is, 7.634 mg.

5 0
3 years ago
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