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yuradex [85]
3 years ago
13

An atom of which element has the largest atomic radius?

Chemistry
1 answer:
erastovalidia [21]3 years ago
6 0

Answer:

B) Be

Explanation:

Across the period (going from left to right of the periodic table), the atomic radius decreases. Beryllium is located further on the left of the periodic table compared to the other elements in the option and thus it has the largest atomic radius.

<u>Explanation of trend</u><u>:</u>

Across the period, the number of protons and electrons increases in the atom. Electrons are added to the valence shell, hence the electrons added are not able to shield the increased nuclear charge well. (Since shielding effect is most effective when core electrons shield the valence electrons) Therefore, the effective nuclear charge (ENC) increases. As ENC increases, valence electrons are increasingly attracted to the nucleus. They are drawn closer to the nucleus, and so the atomic radius decreases across the period.

What is ENC?

ENC is the net nuclear charge acting on the valence electron (since the valence electron experiences electrostatic forces of attraction by the positively charged protons in the nucleus, and an electron-electron repulsion force by the core electrons)

➣ ENC

= nuclear charge (atomic no.) - shielding constant (no. of core electrons)

See diagram: black arrow represents the shielding effect (also known as electron-electron repulsion), while the orange arrows represent the nuclear charge (electrostatic forces of attraction)

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The question is incomplete, here is the complete question:

Iron (III) oxide and hydrogen react to form iron and water, like this:

Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)

At a certain temperature, a chemist finds that a 8.9 L reaction vessel containing a mixture of iron(III) oxide, hydrogen, Iron, and water at equilibrium has the following composition.

Compound             Amount

  Fe₂O₃                     3.95 g

     H₂                        4.77 g

     Fe                        4.38 g

    H₂O                      2.00 g

Calculate the value of the equilibrium constant Kc for this reaction. Round your answer to 2 significant digits.

<u>Answer:</u> The value of equilibrium constant for given equation is 1.0\times 10^{-4}

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}

  • <u>For hydrogen gas:</u>

Given mass of hydrogen gas = 4.77 g

Molar mass of hydrogen gas = 2 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

\text{Molarity of hydrogen gas}=\frac{4.77}{2\times 8.9}\\\\\text{Molarity of hydrogen gas}=0.268M

  • <u>For water:</u>

Given mass of water = 2.00 g

Molar mass of water = 18 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

\text{Molarity of water}=\frac{2.00}{18\times 8.9}\\\\\text{Molarity of water}=0.0125M

For the given chemical equation:

Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)

The expression of equilibrium constant for above equation follows:

K_{eq}=\frac{[H_2O]^3}{[H_2]^3}

Concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression.

Putting values in above expression, we get:

K_{c}=\frac{(0.0125)^3}{(0.268)^3}\\\\K_{c}=1.0\times 10^{-4}

Hence, the value of equilibrium constant for given equation is 1.0\times 10^{-4}

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