Question

Two charged particles are a distance of 1.72 m from each other. One of the particles has a charge of 8.08 nC, and the other has a charge of 4.02 nC. (a) What is the magnitude (in N) of the electric force that one particle exerts on the other

Answer 1

The magnitude (in N) of the electric force that one particle exerts on the other is A. F=107.6nN.

F=[(9×10^9) ×(7.10×10^-9) ×(4.42×10^-9)] /(1.62^2)

F=(282.4×10^-9)/2.6244

F=107.6×10^-9N

F=107.6nN

Experiments with electric charges have shown that two charged objects exert electrical forces on each other. The magnitude of the force is linearly proportional to the net charge of each object and inversely proportional to the square of the distance between the objects.

Coulomb's law for calculating electrostatic forces. This force arises from the interaction between two charged objects (or point charges), the magnitude of which is calculated by F = kQ1Q2r2 F = k Q 1 Q 2 r2.

Learn more about the electric field  here: brainly.com/question/14372859

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