Answer:
The bird's speed immediately after swallowing is 4.98 m/s.
Explanation:
Given that,
Mass of bird = 290 g
Speed = 6.2 m/s
Mass of sees = 9.0 g
Speed = 34 m/s
We need to calculate the bird's speed immediately after swallowing
Using conservation of momentum
Put the value into the formula
Hence, The bird's speed immediately after swallowing is 4.98 m/s.
.75(m/s)^2
Use this picture
If you know the two on the bottom you multiply them but if you only know the top and one on the bottom you divide
Answer:
magnitude of v = 2.5 m/s, and in the same direction as the initial velocity of the 5 kg ball.
Explanation:
We use conservation of linear momentum in an elastic collision to solve for the unknown velocity v:
Pi = Pf
5 kg * 5 m/s + 10 kg * 0 m/s = 5 kg * 0 m/s + 10 kg * v
25 kg m/s = 10 kg * v
v = 25/10 m/s
v = 2.5 m/s
and in the same direction as the initial velocity of the 5 kg ball.
Answer:
1.176m
Explanation:
Local ambient pressure(P1) = 100 kPa
Absolute pressure(P2)=260kPa
Net pressure=absolute pressure-local ambient absolute pressure
Net pressure=P1(absolute pressure)-P2(local ambient absolute pressure)
Net pressure=260-100=160kPa
Pressure= ρgh
160kPa=13600*10*h
h=
h=1.176m
