There would be very less percentage loss<span> of the kinetic energy during </span>the conversion<span> to internal energy, assuming that there is less air in the </span>surroundings<span>. Also, the friction will contribute to the conversion where if it is, the percentage loses is negligible.</span>
Explanation:
The left side of the periodic table has elements that have less number of electrons in the valence shell.
These elements loose electrons easily.These elements appear as metals or metalloids in nature.These are hard solids.Their inter molecular forces are very strong.
The right side of the periodic table has elements that have more number of electrons in the valence shell.
These elements gain electrons easily.These elements appear as non metals most of which are gases.Their inter molecular forces are weak.
Answer:


Explanation:
Here mass density of rod is varying so we have to use the concept of integration to find mass and location of center of mass.
At any distance x from point A mass density


Lets take element mass at distance x
dm =λ dx
mass moment of inertia

So total moment of inertia

By putting the values

By integrating above we can find that

Now to find location of center mass


Now by integrating the above


So mass moment of inertia
and location of center of mass 
Answer:
Third → First → Second → Fourth
Explanation:
Initially helium and Hydrogen in abundance started to form atoms
Following the atoms formation by hydrogen and helium bombardment of new matter into the Earth took place.
The bombardment of matter resulted in separation of Earth into respective layers based on the weight of the matter.
A primitive ocean was created as a result of off gassing of the volcanoes.
Answer:
Increases
Explanation:
Since power P=IV
Then it means when current increases, the power increases hence brightness increases. I represent current, P is power and v is voltage.
Current of capacitor when in series connection is given by

where I is current across capacitor, f is frequency, C is capacitance and v is voltage across capacitance. From this second formula, it is evident that an increase in capacitance increases the current across the capacitor. Therefore, if current increases, power also increases leading to an increase in brightness