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Fed [463]
2 years ago
9

WHICE group of domain-specific words belongs only to math domain

Mathematics
1 answer:
s2008m [1.1K]2 years ago
6 0

Answer:

The major field of anthroplogy and evolutionary and paleo anthropological perspectives on the origin of humankind

You might be interested in
Jennifer is saving money to buy a bike. The bike costs $245. She has $125 saved, and each week she adds $15 to her savings. How
Lady bird [3.3K]
It will take her 8 weeks to have enough money for a bike. I made the equation 125+15x=245 and multiplied 15 by 8 to get exactly 245
8 0
3 years ago
A recent survey found that 30% of telephone users have switched completely to cell phone use (i.e. they do not have landlines in
Genrish500 [490]

Answer:

The probability that exactly 30% of these 10 telephone users do not have landlines in their homes is 0.2668.

Step-by-step explanation:

We are given that a recent survey found that 30% of telephone users have switched completely to cell phone use (i.e. they do not have landlines in their homes).

A random sample of 10 of these customers is selected.

The above situation can be represented through binomial distribution;

P(X = r) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r}; x = 0,1,2,3,......

where, n = number of trials (samples) taken = 10 customers

            r = number of success = 30% of 10 = 3

            p = probability of success which in our question is the probability

                  that telephone users do not have landlines in their homes,

                   i.e. p = 30%

Let X = <u><em>Number of telephone users who do not have landlines in their homes</em></u>

So, X ~ Binom(n = 10, p = 0.30)

Now, the probability that exactly 30% of these 10 telephone users do not have landlines in their homes is given by = P(X = 3)

           P(X = 3) =  \binom{10}{3}\times 0.30^{3} \times (1-0.30)^{10-3}

                         =  120 \times 0.30^{3} \times 0.70^{7}

                         =  <u>0.2668</u>

4 0
3 years ago
An analysis of sales records for the last 120 weeks gives the following results. Assuming that these past data are a reliable gu
Mila [183]

Answer:

(a) 0.5333

(b) 0.6583

(c) 0.5583

(d) 0.7083

(e) 0.6167

Step-by-step explanation:

Denote the events as follows:

<em>A</em> = a competitor will advertise

<em>NA </em>= a competitor will not advertise

<em>L </em>= Low sales will be achieved

<em>M </em>= Medium sales will be achieved

<em>H </em>= High sales will be achieved

The data provided is of the form:

          Low (L)    Medium (M)    High (H)    Total    

A            32                   14                 18               64

NA          21                   12                 23              56

Total      53                  26                 41              120

The probability of an event <em>E</em> is:

P(E)=\frac{n(E)}{N}

n (E) = favorable outcomes of event <em>E</em>

N = Total number of outcomes

(a)

Compute the probability that next week the competitor will advertise as follows:

P(A)=\frac{n(A)}{N}=\frac{64}{120}=0.5333

Thus, the probability that next week the competitor will advertise is 0.5333.

(b)

Compute the probability that next week sales will not be high as follows:

P(H^{c})=1-P(H)=1-\frac{n(H)}{N}=1-\frac{41}{120}=\frac{120-41}{120}=0.6583

Thus, the probability that next week sales will not be high is 0.6583.

(c)

The events of achieving a medium or high sales are mutually exclusive.

Since the sales achieved will either be medium or high. They cannot be both.

So, P (M ∩ H) = 0.

Compute the probability that next week there will be medium or high sales will be achieved as follows:

P(M\cup H)=P(M)+P(H)=\frac{26}{120}+\frac{41}{120}=\frac{26+41}{120}=0.5583

Thus, the probability that next week there will be medium or high sales will be achieved is 0.5583.

(d)

Compute the probability that next week either the competitor will advertise, or only low sales will be achieved as follows:

P(A\cup L)=P(A)+P(L)-P(A\cap L)=\frac{64}{120}+\frac{53}{120}-\frac{32}{120}=\frac{85}{120}=0.7083

Thus, the  the probability that next week either the competitor will advertise, or only low sales will be achieved is 0.7083.

(e)

Compute the probability that next week either the competitor will not advertise, or high sales will be achieved as follows:

P(NA\cup H)=P(NA)+P(H)-P(NA\cap H)=\frac{56}{120}+\frac{41}{120}-\frac{23}{120}=\frac{74}{120}=0.6167

Thus, the  the probability that next week either the competitor will not advertise, or high sales will be achieved is 0.6167.

8 0
4 years ago
3. The width of a rectangle is 3x – 7. The length of the rectangle is 4x +5.
garri49 [273]

Answer:

D. 14x - 4

Step-by-step explanation:

P = 2(L + W)

P = 2(4x + 5 + 3x - 7)

P = 2(7x - 2)

P = 14x - 4

3 0
3 years ago
Verify the identity.​
sleet_krkn [62]

Answer:

Van Wayne en diere net banako maile Sondag wetenskap en

5 0
4 years ago
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