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3 years ago

methane is a flammable compound made of carbon and hydrogen atoms. how could you seperate the carbon and hydrogen in methane

1 answer:

7 0

As we know methane is an Alkane to separate an Alkane We use fractional distillation to put each liquid into its fraction with the right temperature group

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A catalyst

kotegsom [21]

A catalyst speeds up the rate of reaction so the answer is B.

8 0

3 years ago

How many moles of methane are in 20.32 x 10^16 molecules

Marizza181 [45]

Taking into account the definition of avogadro's number, 3.37×10⁻⁷ moles of methane are 20.32×10¹⁶ molecules.

First of all, you have to know that Avogadro's number indicates the number of particles of a substance (usually atoms or molecules) that are in a mole.

Its value is 6.023×10²³ particles per mole and it applies to any substance.

Then you can apply the following rule of three: if 6.023×10²³ molecules are contained in 1 mole of methane, then 20.32×10¹⁶ molecules are contained in how many moles of methane?

amount of moles of methane= (20.32×10¹⁶ molecules × 1 mole)÷ 6.023×10²³ atoms

Solving:

<u><em>amount of moles of methane= 3.37×10⁻⁷ moles</em></u>

Finally, 3.37×10⁻⁷ moles of methane are 20.32×10¹⁶ molecules.

Learn more about Avogadro's Number:

7 0

2 years ago

You have 5 cars and you double that amount.How much cars do you have.

Nostrana [21]

Answer:

10 cars

Explanation:

the double of 5 is 10

5+5=10

5 0

3 years ago

For each of the following cases, identify the order with respect to the reactant, A. Case (A ----> product)

damaskus [11]

Answer:

The answers to the question are

1. 2nd and above order order

2. 2nd order

3. 1/2 order

4. 1st order

5. 0 order

Explanation:

We have $\frac{N}{N_{0} } = e^{-\lambda t}$

1. For nth order reaction half life $t_{\frac{1}{2} }$ ∝ $\frac{1}{[A_{0} ]^{n-1} }$

Therefore for a 0 order reaction increasing concentration of the reactant there will increase $t_{\frac{1}{2} }$

First order reaction is independent [A₀].

Second order reaction [A₀] decrease, increase.

Similarly for a third order reaction

1. 2nd order

2. 2nd order reaction

3. Order of reaction is 1/2.

4. 1st order reaction.

5. Zero order reaction.

5 0

3 years ago

If one iron nail weighs 2.0 grams, what would be the mass of 6.022 x 10^23 nails?

Maru [420]

Answer:

$1.2x10^{24}g$

Explanation:

Hello!

In this case, it is possible to treat this problem by using a proportional factor which indicates one iron nail equals 2.0 grams:

$\frac{2.00g}{1nail}$

Now, for an amount of 6.022x10²³ nails, the corresponding mass will be:

$6.022x10^{23}nail*\frac{2.00g}{1nail} \\\\1.2x10^{24}g$

Best regards!

8 0

3 years ago