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3 years ago

methane is a flammable compound made of carbon and hydrogen atoms. how could you seperate the carbon and hydrogen in methane

1 answer:

7 0

As we know methane is an Alkane to separate an Alkane We use fractional distillation to put each liquid into its fraction with the right temperature group

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Nucleosynthesis began when _____ and ended when _____

lutik1710 [3]

<h2>Nucleosynthesis.</h2>

Explanation:

A. the Big Bang occurred; the Big Crunch occurred

Nucleosynthesis is the process by which new atomic nucleus are formed from pre-existing protons and neutrons.

According to cosmic theories, the nucleosythesis began one minute after the occurrence of Big bang and will end with the big Crunch.

The Big bang theory describes all the processes by which the universe came into existence while the big crunch theory explains how universe will come to an end. A

5 0

3 years ago

An FAS calibration curve (absorbance, y-axis vs. FAS in g/mL) gave an equation he regression line of: y-3678(x)+0.056. If an unk

mezya [45]

Answer:

FAS concentration = 1.61*10^-4M

Explanation:

Beer Lambert's law relates the absorbance (A) of a substance to its concentration (c) as:

$A = \epsilon lc----(1)$

where ε = molar absorption coefficient

l = path length

A plot of 'A' vs 'c' gives a straight line with slope = εl

In addition absorbance (A) is related to % Transmittance (%T) as:

A = 2-log%T----(2)

For the FAS solution, the corresponding calibration fit is given as:

y = 3678(x) + 0.056

This implies that the slope = εl = 3678

It is given that %T = 25.6%

$A = 2-log(25.6)=0.592$

Based on equation(1):

$c = \frac{A}{\epsilon l}=\frac{0.592}{3678}=1.61*10^{-4}M$

8 0

3 years ago

How many moles are present in 356.4 g of NiBr3

lozanna [386]

1.194 mol

(remember to use sig figs!)

8 0

3 years ago

Balence the following equation : _____ NH3 --------> _____ N2 + _____ H2

Ksenya-84 [330]

2 NH3 -> 1 N2 + 3 H2

Explanation:

That would be the answer to this

8 0

3 years ago

I have 2 samples of solid chalk (aka calcium carbonate). Sample A has a total mass of 4.12 g and Sample B has a total mass of 19

IRINA_888 [86]

Answer:

A) Sample B has more calcium carbonate molecules

Explanation:

M = Molar mass of calcium carbonate = 100.0869 g/mol

$N_A$ = Avogadro's number = $6.022\times 10^{23}\ \text{mol}^{-1}$

For the 4.12 g sample

Moles of a substance is given by

$n=\dfrac{m}{M}\\\Rightarrow n=\dfrac{4.12}{100.0869}\\\Rightarrow n=0.0411\ \text{mol}$

Number of molecules is given by

$nN_A=0.0411\times 6.022\times 10^{23}=2.48\times 10^{22}\ \text{molecules}$

For the 19.37 g sample

$n=\dfrac{19.37}{100.0869}\\\Rightarrow n=0.193\ \text{mol}$

Number of molecules is given by

$nN_A=0.193\times 6.022\times 10^{23}=1.16\times 10^{23}\ \text{molecules}$

$1.16\times 10^{23}\ \text{molecules}>2.48\times 10^{22}\ \text{molecules}$

So, sample B has more calcium carbonate molecules.

The ratio of the elements of carbon, oxygen, calcium atoms, ions, has to be same in both the samples otherwise the samples cannot be considered as calcium carbonate. Same is applicable for impurities. If there are impurites then the sample cannot be considered as calcium carbonate.

7 0

3 years ago