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Semmy [17]
3 years ago
13

The country like Nepal with diversity must have competition and cooperation justify​

Chemistry
1 answer:
Len [333]3 years ago
3 0
Help????? You need to write as if you are Dmitri Mendeleev and you have just made your proposed version of the periodic table. You need to write to the Royal Society of Chemistry in London explaining:
• Who you are
• What your periodic table is like, the groups, elements and features
• Why you think your periodic table is correct
• How you have built on the work of others or why you think their work is not
correct
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Is precipitate in water an electrolyte solution
vagabundo [1.1K]
When no ions are produced, or the ion content is low, the solute is a non-electrolyte. Non-electrolytes do not conduct electricity or conduct it to a very small degree. In an aqueous solution a strong electrolyte is considered to be completely ionized, or dissociated, in water, meaning it is soluble
4 0
3 years ago
Which of these molecules has the same number of shared electron pairs as unshared electron pairs? (a) hcl, (b) h2s, (c) pf3, (d)
Paul [167]
<span>H2S has 2 bonds which means that it has two shared electron pairs. It has 2 lone pairs on electrons. It's the only one where the 2 are the same.</span>
8 0
4 years ago
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HELP PLS 50 POINTSSSS
Alenkasestr [34]

Answer:

Carbon dioxide is a product (cellular respiration)

Carbon dioxide is a reactant(photosynthesis)

Carried out in animals(cellular respiration)

Carried out in plants(both)

Chemical reaction(cellular respiration)

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Produces usable energy source(photosynthesis)

Your welcome!!! Plz mark brainliest.

4 0
3 years ago
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The combustion of 0.25 mol of an unknown organic compound results in the release of 320 kJ of energy. Which of the compounds in
vichka [17]

Answer: C. ethanol

The enthalpy of combustion is the amount of heat produced when one mole of ethanol undergoes complete combustion at 25 ° C and 1 atmosphere pressure, yielding products also at 25 ° C and 1 atm.

<u>The enthalpy of combustion of the unknown compound is</u>

ΔH = - 320 kJ / 0.25 mol = - 1280 kJ / mol

<u>To choose a probable compound according to this combustion enthalpy, we must evaluate the deviation in relation to the values reported in the literature for the three probable compounds</u> (methane, ethylene and ethanol). The deviation (e%) will be calculated according to the following equation,

e% =  ( | ΔHx - ΔH | / ΔHx ) x 100%

where ΔHx is the enthalpy of combustion of the probable compound.

The following table shows the combustion enthalpies of the probable compounds and their deviation in relation to the enthalpy of ΔH = - 1280 kJ / mol

Compound Enthalpy of combustion (kJ/mol)   Deviation

Methane                        - 890.7                                 43.8%

Ehylene                         -1411.2                                   9.3%

Ethanol                        -1368.6                                    6.5%

According to the previous table, we can say that the most probable compound is ethanol, since it has the smallest deviation in relation to the experimental enthalpy value of combustion.

5 0
4 years ago
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A plane flew for 2 hours at 467 mph (mile per hour)and 5 hours at 536 mph. How far did the plane fly miles?
Andreyy89

Answer:

the plane flew 3614 miles

7 0
3 years ago
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