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Andrei [34K]
2 years ago
11

Eggs do not contain sugar. Explain why they have such high energy values.​

Chemistry
2 answers:
MaRussiya [10]2 years ago
7 0

Answer:

because they have protein inside them dummy its easy therefore they did not have sugar

Explanation:

Kay [80]2 years ago
3 0

Answer:

becuz they have protien inside them dumy its easy

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4 years ago
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A coyote and an oak tree both reproduce ?
Irina18 [472]

Answer:

<h2>YES</h2>

Explanation:

Coyotes and oak trees are multicellular organisms and multicellular organisms reproduce asexually and sexually.

Many multicellular lower plants give off asexual spores, either aerial or motile and aquatic (zoospores), which may be uninucleate or multinucleate.

4 0
3 years ago
A container contains a mixture of hydrogen, oxygen and nitrogen gases. The pressure of hydrogen is 78 kPa. The pressure of oxyge
Nuetrik [128]

<u>Answer:</u> The total pressure of the container is 140.2416 kPa

<u>Explanation:</u>

Dalton's law of partial pressure states that the total pressure of the system is equal to the sum of partial pressure of each component present in it.

To calculate the total pressure, we use the law given by Dalton, which is:

P_T=p_{H_2}+p_{O_2}+p_{N_2}

We are given:

Vapor pressure of hydrogen gas, p_{H_2} = 78 kPa

Vapor pressure of oxygen gas, p_{O_2} = 2.4416 kPa

Vapor pressure of nitrogen gas, p_{N_2} = 59.8 kPa

Putting values in above equation, we get:

P_T=78+2.4416+59.8\\\\P_T=140.2416kPa

Hence, the total pressure of the container is 140.2416 kPa

7 0
3 years ago
The Ksp of Al(OH)3 is 2.0 x 10-31 at 298 K. What is \DeltaGo (at 298 K) for the precipitation of Al(OH)3 according to the equati
Veronika [31]

ΔG° = -RT ln K

ΔG° = -RT ln 1/Ksp (reverse reaction, solid (Al(OH)₃ not count for equilibrium constant-K)

ΔG° = -RT ln 1/Ksp

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ΔG° = -175.132 kJ/mol

8 0
2 years ago
How many molecules are in the substance formula of 2C6H1206 (use coefficients)
FrozenT [24]

<u>Answer:</u> The number of formula units present in 2 moles of C_6H_{12}O_6 are 1.2044\times 10^{24}

<u>Explanation:</u>

Formula units are defined as the number of molecules or atoms present in 1 mole of a compound or element respectively.

According to mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of formula units

Here, 2 represents the number of moles of C_6H_{12}O_6

We are given:

Moles of C_6H_{12}O_6 (glucose) = 2 moles

Number of formula units of C_6H_{12}O_6=(2\times 6.022\times 10^{23})=1.2044\times 10^{24}

Hence, the number of formula units present in 2 moles of C_6H_{12}O_6 are 1.2044\times 10^{24}

6 0
3 years ago
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