Answer:
In the final solution, the concentration of sucrose is 0.126 M
Explanation:
Hi there!
The number of moles of solute in the volume taken from the more concentrated solution will be equal to the number of moles of solute in the diluted solution. Then, the concentration of the first solution can be calculated using the following equation:
Ci · Vi = Cf · Vf
Where:
Ci = concentration of the original solution
Vi = volume of the solution taken to prepare the more diluted solution.
Cf = concentration of the more diluted solution.
Vf = volume of the more diluted solution.
For the first dillution:
26.6 ml · 2.50 M = 50.0 ml · Cf
Cf = 26.6 ml · 2.50 M / 50.0 ml
Cf = 1.33 M
For the second dilution:
16.0 ml · 1.33 M = 45.0 ml · Cf
Cf = 16.0 ml · 1.33 M / 45.0 ml
Cf = 0.473 M
For the third dilution:
20.0 ml · 0.473 M = 75.0 ml · Cf
Cf = 20.0 ml · 0.473 M / 75.0 ml
Cf = 0.126 M
In the final solution, the concentration of sucrose is 0.126 M
Its the complete transfer of valence electrons between atoms
Answer:
D) contains more OH– ions than H+ ions
Explanation:
THESE ARE THE OPTIONS FOR THE QUESTION
A) causes some indicators to change color B) conducts electricity C) contains more H+ ions than OH– ions D) contains more OH– ions than H+ ions
Base can be regarded as substance which can dissociates in water then form hydroxide ions (OH–) .
Bases can be regarded as compounds which break into hydroxide ions I.e (OH-) with more other compounds if put in an aqueous solution. Hence it contains more OH– ions
