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STALIN [3.7K]
3 years ago
15

A student combines a solution of NaCl(aq) with a solution of AgNO3(aq), and a precipitate forms. Assume that 50.0mL of 1.0MNaCl(

aq) and 50.0mL of 1.0MAgNO3(aq) were combined. According to the balanced equation, if 50.0mL of 2.0MNaCl(aq) and 50.0mL of 1.0MAgNO3(aq) were combined, the amount of precipitate formed would:_________
Chemistry
1 answer:
gtnhenbr [62]3 years ago
8 0

Answer:

Based on the given information, the balanced equation is:

NaCl + AgNO3 = AgCl + NaNO3

Now the moles present in 50 ml of 1M NaCl is,

= 50 * 1/1000 mole = 0.05 mole

And the moles present in 50 ml of 1 M AgNO3 is,

= 50*1/1000 mole = 0.05 mole

Therefore, 0.05 mole of NaCl combines with 0.05 mole of AgNO3 to precipitate 0.05 mole of AgCl.

Now in the second case, to balance the chemical equation, 50 ml of 2 M NaCl combines with 50 ml of 1 M AgNO3. So, the moles present in 50 ml of 2 M NaCl will be,

= 50*2/1000 mole = 0.1 mole

However, the amount of AgNO3 in the second case is not changing, therefore, the amount of AgCl precipitated will be,

= 0.1 - 0.05 = 0.05 mole

Therefore, the amount of precipitate would not change as there is no change in the amount of AgNO3.

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Answer:

viscosity

Explanation:

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3 years ago
100 ml is drawn from 0.1 M solution of KCl and added to 900 ml of water. What is the
grandymaker [24]

Answer:

The new concentration will be 0.01 M.

Explanation:

To determine the new concentration we use the following formula.

concentration (1) × volume (1) = concentration (2) × volume (2)

concentration (1) = 0.1 M

volume (1) = 100 mL

concentration (2) = unknown

volume (2) = 100 mL + 900 mL = 1000 mL

concentration (2) = [concentration (1) × volume (1)] / volume (2)

concentration (2) = (0.1 × 100) / 1000 = 0.01 M

3 0
3 years ago
Determine the volume of 3.30 mol of a gas at 25°C and 0.995 atm.
Alexxx [7]

Answer:

V = 81.14 L

Explanation:

Given data:

Volume of gas = ?

Number of moles = 3.30 mol

Temperature of gas = 25°C

Pressure of gas = 0.995 atm

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K

T = temperature in kelvin

Now we will convert the temperature.

25+273 = 298 K

now we will put the values in formula:

V = 3.30 mol 0.0821 atm.L/ mol.K   298 K / 0.995 atm

V = 80.74 L. atm / 0.995 atm

V = 81.14 L

4 0
3 years ago
A covalent bond is dependant on the electrons from an atom being________
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They depend on the electrons from an atom being distributed among them or shared, within their specialized bonding orbitals.
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Answer:

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Explanation:

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