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goblinko [34]
3 years ago
8

Copper metal can exist as ______________ ions.

Chemistry
1 answer:
denis-greek [22]3 years ago
3 0

Answer:

Copper metal can exist as <em><u>Cu+</u></em><em><u> </u></em><em><u>and </u></em><em><u>Cu2+</u></em><em><u> </u></em>

ions.

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Provide the reagents necessary to carry out the following conversion.
Alika [10]

Answer:

see explanation below

Explanation:

First, you are not providing the reaction to do the conversion. However, in picture 1, I attached a reaction that match perfectly with the description of this question, so I hope it could be.

Now picture 2, shows you the correct steps of conversion, now let me explain a little here the mechanism:

The first step in all options is the same. Those reagents works to do an oxidation of the methyl group to a carboxilic acid, and then, we transform toluene into benzoic acid. Now the second step in the first option involves Cl2 in light, and this only works to do halide alkylation in acyclic chains, so this would not work in the reaction to get the final product. In option 2, we have Cl2/FeCl3, and this will promote a friedel craft alkylation, and Chlorine will go to the para position of the ring, so we can exclude this option. However option 3 and 4 uses SOCl2, and this is often used to convert the hydroxile group of a molecule into an halide, so these two options works in the second step.

Now, for the step 3, option 4 uses grignard reagent with (CH3CH2)2CH2MgBr as reagent, but this will only form a larger chain and the CH3CH2 will not break, so, this option is discarted, and finally option 3 will be the correct one. Picture 2 shows you every step.

6 0
3 years ago
Pls can someone help me
BaLLatris [955]

Answer:

Explanation:

B

3 0
3 years ago
Read 2 more answers
True/False: All of the elements combine in a variety of ways to make up all living and all nonliving things
likoan [24]

Answer:

true

Explanation:

5 0
3 years ago
One mole of an ideal gas, CP=3.5R, is compressed adiabatically in a piston/cylinder device from 2 bar and 25 oC to 7 bar. The pr
Luda [366]

Answer:

the entropy change of the gas is ΔS= 2.913 J/K

Explanation:

starting from the first law o thermodynamics for an adiabatic reversible process

ΔU= Q - W

where

ΔU = change in internal energy

Q= heat flow = 0 ( adiabatic)

W = work done by the gas

then

-W=  ΔU

also we know that the ideal compression work Wcom= - W , then Wcom = ΔU. But also for an ideal gas

ΔU= n*cv* (T final - T initial)

where

n=moles of gas

cv= specific heat capacity at constant volume

T final =T₂= final temperature of the gas

T initial =T₁= initial temperature of the gas

and also from an ideal gas

cp- cv = R → cv = 7/2*R - R = 5/2*R

therefore

W com = ΔU = n*cv* (T final - T initial)

for an ideal gas under a reversible adiabatic process ΔS=0 and

ΔS= cp*ln(T₂/T₁) - R* ln (P₂/P₁) =0

therefore

T₂ = T₁* (P₂/P₁)^(R/cp) = T₁* (P₂/P₁)^(R/(7/2R))=  T₁* (P₂/P₁)^(2/7)

replacing values T₁=25°C= 298 K

T₂ =T₁* (P₂/P₁)^(2/7)  = 298 K *(7 bar/2 bar)^(2/7) = 426.25 K

then

W com = ΔU = n*cv* (T₂- T₁)  

and the real compression work is W real = 1.35*Wcom , then

W real = ΔU

W real = 1.35*Wcom = n*cv* (T₃ - T₁)

T₃ = 1.35*Wcom/n*cv + T₁ = 1.35*(T₂- T₁) + T₁ =1.35*T₂ - 0.35*T₁ = 1.35*426.25 K - 0.35 *298 K = 471.14 K

T₃ = 471.14 K

where

T real = T₃  

then the entropy change will be

ΔS= cp*ln(T₃/T₁) - R* ln (P₂/P₁) = 7/2* 8.314 J/mol K *ln(471.14 K /298 K ) - 8.314 J/mol K* ln (7 bar / 2 bar)  = 2.913 J/K

ΔS= 2.913 J/K

5 0
3 years ago
What is Anion and it’s charge for Calcium and Oxygen
LekaFEV [45]

Answer:

Anion is negatively charged particle.

Calcium +2. Its cation

Oxygen -2

Explanation:

An anion is a charged particle with a negative charge. Anions has charge of -1

Oxygen require two electrons to complete its octet and hence its charge is -2

Calcium is  a cation and has a positive charge of +2

6 0
3 years ago
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