Answer:
<h2>A.Step-by-step explanation:
The given formula is
Where and
To solve for , first we need to move
Then, we move the term 1
Finally, we move the factor
Replacing given values, we have
Thereofre, the right answer is A.
Using the relationships between
1 answer:
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The given quadratic describes a parabola that opens upward. Its one absolute extreme is a minimum that is found at x = -3/2. The value of the function there is
(-3/2 +3)(-3/2) -1 = -13/4
The one relative extreme is a minimum at (-1.5, -3.25).
_____
For the parabola described by ax² +bx +c, the vertex (extreme) is found where
x = -b/(2a)
Here, that is x=-3/(2·1) = -3/2.
(-3/2 +3)(-3/2) -1 = -13/4
The one relative extreme is a minimum at (-1.5, -3.25).
_____
For the parabola described by ax² +bx +c, the vertex (extreme) is found where
x = -b/(2a)
Here, that is x=-3/(2·1) = -3/2.
Answer:
False. Correct ratio is
Step-by-step explanation:
the ratio of sine is opposite over hypotenuse
(opposite is the side across from the angle and hypotenuse it the slant line in the triangle)