"The distance between the front and rear wheels of a 2280 kg car is 3.15 m. The car’s center of gravity lies in the middle of th
e car, 1.05 m behind the front wheels. When the car is at rest, what is the ratio of the force exerted by the ground on the front wheels to that exerted on the rear wheels?"
1 answer:
Answer:
2
Explanation:
Hello to solve this problem we must initially draw the free body diagram of the car, and remember that for a body to be in balance the sum of its moments must be zero.
When this equation is raised, we can find the relationship between the forces of the front and rear wheel, and the complete procedure is attached.
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Answer:
1. 18.25 m/s
2. 0 m/s
Explanation:
1.So the centripetal acceleration of the ball at this lowest point must be, taking gravity into account
The speed at this point would then be
2. Similarly, if T = mg, then the centripetal acceleration must be
As the ball has no centripetal acceleration, its speed must also be 0 as well.