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Natalija [7]
3 years ago
7

Two charged particles move in the same direction with respect to the same magnetic field. particle 1 travels two times faster th

an particle 2. however, each particle experiences a magnetic force of the same magnitude. find the ratio q1/q2 of the magnitudes of the charges.
Physics
1 answer:
MaRussiya [10]3 years ago
6 0
<span>0.166666666667

Hope this helped!
STSN</span>
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The meaninn of dynamics<br>​
Studentka2010 [4]

Answer:

Dynamics is just a nice word used in physics denoting a branch of physics, related to the study of forces. Usually these forces are not in mechanical equilibrium, else the branch would be statics.

6 0
2 years ago
A dielectric material, such as Teflon , is placed between the plates of a parallel-plate capacitor without altering the structur
Setler [38]

Answer:

1. The voltage decreases because of the insertion of the Teflon.

Explanation:

When we placed the dielectric medium/material between the plates of the capacitor. It increases the capacitance. Increase in capacitance means that the electric field between the plates will decrease and thus there will be a decrease in voltage. As we know that the capacitance has an inverse relation with the electric field between the plates. Mathematically,

q = CV\\C = Q/V

where C is capacitance, V is Voltage and q is a charge.

By putting "Teflon between the plates of capacitor there will be a decrease in voltage."

4 0
3 years ago
(8 points) Air is used as the working fluid in a simple ideal Brayton cycle that has a pressure ratio of 12, a compressor inlet
trapecia [35]

Answer:

a ) \dot m = 351.49 kg/s

b)  \dot m_{actual} = 1046.15 kg/s

Explanation:

given data:

pressure ration rp = 12

inlet temperature = 300 K

TURBINE inlet temperature  = 1000 K

AT the end of isentropic process (compression) temperature is

\frac{T_2'}{T_1} = rp ^{\frac{\gamma -1}{\gamma}}

\frac{T_2'}{300} = 12^{\frac{1.4 -1}{1.4}}

T_2' = 610.181 K

AT the end of isentropic process (expansion) temperature is

\frac{T_3}{T_4'} = rp ^{\frac{\gamma -1}{\gamma}}

\frac{1000'}{T_4'} = 12^{\frac{1.4 -1}{1.4}}

T_4' = 491.66 K

isentropic work is given as

w(compressor) = CP (T_2' -T_1)

w = 1.005(610.18 - 300)

w = 311.73 kJ/kg

w(turbine) = 1.005( 1000 - 491.66)

w(turbine) = 510.88 kJ/kg

a) mass flow rate for isentropic process is given as

\dot m = \frac{70000}{510.88 - 311.73}

\dot m = 351.49 kg/s

b) actual mass flow rate uis given as

\dot m_{actual} = \frac{70000}{51.088\times 0.85 - \frac{311.73}{0.85}}

\dot m_{actual} = 1046.15 kg/s

6 0
3 years ago
What is the kinetic energy of a 150 gram object moving at a velocity of 100 m/s?
Alex Ar [27]

Answer:

750 J

Explanation:

lets convert mass into kg first , 150 /1000 = 0.15 kg

kinetic energy =  \frac{mv^{2} }{2} =  \frac{0.15*100^{2} }{2}  = 750 J

3 0
3 years ago
A student makes the following statement
Aliun [14]

Answer:

The current is not used up. The electrons flow through the entire circuit and this travel is the current. They flow until they are not charged anymore. That is also why the circuit must be closed or else electrons would escape not just light it up for a second then go out.

Explanation:

8 0
4 years ago
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